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n/(n)^(m-1)
1 import java.io.*; 2 import java.math.*; 3 import java.util.*; 4 5 public class Main { 6 static BigInteger gcd(BigInteger a,BigInteger b) 7 { 8 if(b.equals(BigInteger.ZERO))return a; 9 else return gcd(b,a.mod(b)); 10 } 11 public static void main(String arg[]) 12 { 13 int T; 14 int n,m; 15 Scanner cin = new Scanner(System.in); 16 T = cin.nextInt(); 17 while( T > 0 ) 18 { 19 m = cin.nextInt(); 20 n = cin.nextInt(); 21 BigInteger tmp1 = BigInteger.valueOf(n); 22 BigInteger tmp2 = BigInteger.valueOf(m).pow(n-1); 23 BigInteger tt = gcd(tmp1,tmp2); 24 tmp1 = tmp1.divide(tt); 25 tmp2 = tmp2.divide(tt); 26 System.out.println(tmp1+"/"+tmp2); 27 T--; 28 } 29 } 30 }
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原文地址:http://www.cnblogs.com/cnblogs321114287/p/4777373.html