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数据库环境：SQL SERVER 2005
有数据如图1，字段id是序号，id相同的为一组，createtime为创建时间。要求：
将createtime为最新时间所在的组排在前面，同时，同一组内的数据按createtime降序排序。
最终结果如图2所示
实现思路：
1.用分析函数取组内最大值
2.按照组内最新时间和创建时间降序排序
SQL实现：
/*测试数据*/ WITH x0 AS ( SELECT 1 AS id , 100 AS data , CONVERT(DATETIME, ‘2015-09-01 12:23:56‘) AS createtime UNION ALL SELECT 1 AS id , 24 AS data , CONVERT(DATETIME, ‘2015-09-02 18:25:26‘) AS createtime UNION ALL SELECT 2 AS id , 68 AS data , CONVERT(DATETIME, ‘2015-09-01 08:46:12‘) AS createtime UNION ALL SELECT 2 AS id , 360 AS data , CONVERT(DATETIME, ‘2015-09-01 00:52:58‘) AS createtime UNION ALL SELECT 2 AS id , 200 AS data , CONVERT(DATETIME, ‘2015-09-03 10:08:36‘) AS createtime UNION ALL SELECT 3 AS id , 70 AS data , CONVERT(DATETIME, ‘2015-09-02 13:48:12‘) AS createtime UNION ALL SELECT 4 AS id , 108 AS data , CONVERT(DATETIME, ‘2015-08-31 03:11:23‘) ),/*分析函数求组内最新时间*/ x1 AS ( SELECT id , data , createtime , MAX(createtime) OVER ( PARTITION BY id ) AS createtime_max FROM x0 )/*对结果集排序*/ SELECT id , data , createtime FROM x1 ORDER BY createtime_max DESC , createtime DESC
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原文地址：http://www.cnblogs.com/boss-he/p/4780088.html
