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template<typename T>
class ThreadsafeQueue
{
private:
mutable std::mutex _mut;
std::queue<std::shared_ptr<T>> _dataQueue;
std::condition_variable _dataCond;
public:
ThreadsafeQueue() = default;
void push(T newValue)
{
std::lock_guard<std::mutex> lock(_mut);
_dataQueue.push (std::make_shared<T>(std::move(newValue)));
_dataCond.notify_one ();
}
void waitAndPop (T &value)
{
std::unique_lock<std::mutex> lock(_mut);
_dataCond.wait (lock, [this]{return !_dataQueue.empty ();});
value = std::move(*_dataQueue.front ());
_dataQueue.pop ();
}
std::shared_ptr<T> waitAndPop ()
{
std::unique_lock<std::mutex> lock(_mut);
_dataCond.wait(lock, [this]{return !_dataQueue.empty ();});
auto pPopedValue = std::move(_dataQueue.front ());
_dataQueue.pop ();
return pPopedValue;
}
bool tryPop (T &value)
{
std::lock_guard<std::mutex> lock(_mut);
if (_dataQueue.empty ()){
return false;
}
value = std::move(*_dataQueue.front ());
_dataQueue.pop ();
return true;
}
std::shared_ptr<T> tryPop ()
{
std::lock_guard<std::mutex> lock(_mut);
if (_dataQueue.empty ()){
return std::make_shared<T>();
}
auto result = std::move(_dataQueue.front ());
_dataQueue.pop ();
return result;
}
bool empty () const
{
std::lock_guard<std::mutex> lock(_mut);
return _dataQueue.empty ();
}
};
这样确实可以实现并发,但是效率极低,因为一次只能有一个线程可以操作,无法发挥并发的真正优势。
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原文地址:http://www.cnblogs.com/wuOverflow/p/4831056.html