码迷,mamicode.com
首页 > 编程语言 > 详细

C语言实现时间差、星期、天数算日期(转)

时间:2015-09-29 23:38:26      阅读:412      评论:0      收藏:0      [点我收藏+]

标签:

原文地址:http://blog.csdn.net/coder_xia/article/details/6566708

最近因为一个项目需要,默认一个时间值,即当天的前一天日期,顺手就将其他的几个功能一并实现了,主要为

1、两个日期之间的时间差

2、某个日期之后,绝对值差值之后的某个日期

3、某年日期,算出星期几

下面见源码:

#ifndef CALCULATE_H

#define CALCULATE_H

 

typedef struct

{

         int year;

         int month;

         int day;

}date;

 

int Leap_Year(int year);

int Calculate(date a,date b);

date Date_String_To_Format(char *string_date);

int Distance_Date(char *string_begin, char *string_end);

int Week(char *string_date);

int Judge(date d1);

date Now_to_Later(date now, int gap);

date Now_To_Fronter(date now, int gap);

 

#endif

 

#include<stdio.h>

#include<stdlib.h>

#include <string.h>

#include "calculate.h"

 

 

 

int month[12]={31,28,31,30,31,30,31,31,30,31,30,31};

  

功能: 将年转化为天

参数:

返回:

sum---转化的天数

修改:

备注:

fast_sky@sina.com

 int Year_To_Day(int year_begin, int year_end)

{

         int sum = 0;

         int number = year_begin;

 

         while(number != year_end)

         {

                   sum = sum + 365 + Leap_Year(year_begin);

                   number++;

         }

 

         return sum;

}

功能:将月转化为天数

参数:

返回:

-----转化完成的天数

修改:

备注:

fast_sky@sina.com

 int Month_To_Day(date now)

{

         int i, day = 0;

 

         for (i = 0; i < now.month - 1; ++i)

         {

                   day = day + month[i];

         }

 

         return (now.month >= 3) ? day + now.day + Leap_Year(now.year) :  day + now.day;

 

}

功能:计算两个日期之间的差值

参数:

begin---起始日期

end----结束日期

返回:

---算出的时间差值

修改:

备注:

fast_sky@sina.com

且begin <= end

 int Calculate(date begin,date end)

{

         return Year_To_Day(begin.year, end.year) - Month_To_Day(begin) + Month_To_Day(end);

}

 

功能:是否为闰年

参数:

返回:

1----成功

0--失败

修改:

备注:

fast_sky@sina.com

 

 int Leap_Year(int year)

{

         return  ((year % 400 == 0) || ((year % 4 == 0)&& (year 0 != 0))) ? 1 : 0;

}

  

 

功能:字符日期转化为结构体格式

参数:

string_date----传入日前格式(20110101)只取前八位,后面不处理

返回:

---转化完成的格式

修改:

备注:

fast_sky@sina.com

 

 date Date_String_To_Format(char *string_date)

{

         char year[5], month[3], day[3];

         date d1;

 

         memset(year, 0x0, sizeof(year));

         memset(month, 0x0, sizeof(month));

         memset(day, 0x0, sizeof(day));

 

         memcpy(year, string_date, 4);

         memcpy(month, string_date+4, 2);

         memcpy(day, string_date+6, 2);

 

         d1.year = atoi(year);

         d1.month = atoi(month);

         d1.day = atoi(day);

 

         return d1;

}

 

功能:计算两者之间的差值

参数:

返回:

sum---计算所得两个日期之间的差值

修改:

备注:

fast_sky@sina.com

 

int Distance_Date(char *string_begin, char *string_end)

{

         date d1,d2;

         int    sum;

 

         d1=Date_String_To_Format(string_begin);

         d2=Date_String_To_Format(string_end);

         if(Judge(d1)&&Judge(d2))

         {

                   if(d1.year<=d2.year)

                   {

                            sum=Calculate(d1,d2);

                   }

                   else

                   {

                            sum=Calculate(d2,d1);

                   }

         }

 

         return sum;

}

 

功能:某年的星期几

参数:

返回:

1--7----传出的星期数

修改:

备注:

fast_sky@sina.com

蔡勒公式

 

 int Week(char *string_date)

{

         date d1;

         int  century = 0;

         int year = 0;

         int weekday = 0;

         int month = 0;

         char ch;

 

         d1=Date_String_To_Format(string_date);

         if (Judge(d1))

         {

                   if (d1.month < 3)

                   {

                            month = d1.month + 12;

                            d1.year--;

                   }

                   else

                            month = d1.month;

                   century = d1.year/100;

                   year = d1.year % 100;

 

                   weekday = year + (year/4)+(century/4)-(2*century)+(26*(month + 1)/10) + d1.day - 1;

                   weekday = (weekday < 0) ? weekday + 7: weekday;

         }       

 

         return (weekday % 7 == 0) ? 7 : weekday % 7;

}

 

功能:从现在日期往后计算多少天之后的日期

参数:

返回:

---多少天之后的日期

修改:

备注:

fast_sky@sina.com

 

 date Now_to_Later(date now, int gap)

{

         date d1;

         int sum, sum_bak;

         int temp;

 

         d1 = now;

         sum = gap;

        

         if(Judge(d1)&&(sum>0) && (sum < 3649270))

         {

                   while(sum>365)

                   {

                            if(d1.month>=3)

                            {

                                     d1.year++;

                                     sum=sum-365-Leap_Year(d1.year);

                            }

                            else

                            {

                                     sum=sum-365-Leap_Year(d1.year);

                                     d1.year++;

                            }

                   }

                   while(sum > 0)

                   {

                            if (d1.month != 2)

                            {

                                     temp = month[d1.month - 1] -d1.day + 1;

                            }

                            else

                            {

                                     temp = month[d1.month - 1] +Leap_Year(d1.year)- d1.day + 1;

                            }

                            sum_bak = sum;

                            sum = sum - temp;

                            if (sum  >= 0)

                            {

                                     d1.month++;

                                     d1.day = 1;

                                     if (d1.month > 12)

                                     {

                                               d1.month = 1;

                                               d1.year++;

                                     }

                                     sum_bak = sum;

                            }

                   }

                   d1.day += sum_bak;

         }

 

         return d1;

}

 

功能:从当前日期往前计算多少天前的日期

参数:

返回:

------计算完成的日期

修改:

备注:

fast_sky@sina.com

 

 date Now_To_Fronter(date now, int gap)

{

         date d1;

         int sum, sum_bak;

         int temp;

 

         d1 = now;

         sum = gap;

        

         if(Judge(d1)&&(sum < 0) && (sum > -3649270))

         {

                   while(sum < -365)

                   {

                            if(d1.month>=3)

                            {

                                     sum=sum+365+Leap_Year(d1.year);

                                     d1.year--;

                            }

                            else

                            {

                                     d1.year--;

                                     sum=sum + 365 + Leap_Year(d1.year);

                            }

                   }

 

                   sum_bak = sum;

 

                   while(sum < 0)

                   {

                            temp =-d1.day;

                            sum = sum - temp;

                            if (sum  <= 0)

                            {

                                     d1.month--;

                                     if (d1.month < 1)

                                     {

                                               d1.month = 12;

                                               d1.year--;

                                     }

                                     if (d1.month == 2)

                                               d1.day  = month[d1.month - 1] + Leap_Year(d1.year);

                                     else

                                               d1.day = month[d1.month - 1];

 

                                     sum_bak = -sum;

                            }

                   }

                   if (sum_bak < 0)

                   {

                            d1.day = d1.day + sum_bak;

                   }else

                   {

 

                            if (d1.month == 2)

                                     d1.day = month[d1.month - 1] + Leap_Year(d1.year) - sum_bak;

                            else

                                     d1.day = month[d1.month - 1] - sum_bak;

                   }

         }

 

         return d1;

}

 

功能:判断输入日期是否合法

参数:

返回:

1----成功

0--失败

修改:

备注:

fast_sky@sina.com

 

 int udge(date d1)

{

         return     ((d1.year > 0 && d1.year <= 9999) &&

                            (d1.month > 0 && d1.month <= 12) &&

    

C语言实现时间差、星期、天数算日期(转)

标签:

原文地址:http://www.cnblogs.com/15157737693zsp/p/4847548.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!