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1. Every non-primitive methods has a toString() method
"source = " +source; //an object of WaterSource
the compiler sees you tring to add a String object("source =") to a WaterSource . Because you can only add a "String" to another String, it says, "I‘ll turn source into a String by calling toString()!" After doing this it can combine the two Strings and pass the resulting String to System.out.println(). Anytime you want to allow this behavior with a class you create, you need only write a toString method.
2. Four ways to initialize the references
①. at hte point the objects are defined. This means that they will always be initialized before the constructor is called.
②. in the constructor for that class.
③. right before you actually need to use the object. This is often called lazy initialization.
④. using instance initialization.
class Soap {
private String s;
Soap() {
print("Soap()");
s = "Constructed";
}
pulbic String toString() { return s; }
}
public class Bath {
private String //Initializing at the point of definition:
s1 = "Happy",
s2 = "Happy",
s3, s4;
private Soap castille;
private int i;
private float toy;
public Bath() {
print("Inside Bath()");
s3 = "Joy";
toy = 3.14f;
castille = new Soap();
}
// Instance initialization:
{ i = 47; }
public String toString() {
if(s4 = null) // Lazy initialization:
s4 = "Joy";
return
"s1 = " + s1 + "\n" +
"s2 = " + s2 + "\n" +
"s3 = " + s3 + "\n" +
"s4 = " + s4 + "\n" +
"i = " + i + "\n" +
"toy = " + toy + "\n" +
"castille = " + castille;
}
public static void main(String[] args) {
Bath b = new Bath();
print(b);
}
}/* output:
Inside Bath();
Soap()
s1 = Happy
s2 = Happy
s3 = Joy
s4 = Joy
i = 47
toy = 3.14
castille = Constructed
*/
3. Inheritance syntax
unless you explicitly inherit from some other class, you implictly inherit from Java‘s standard root class Object
key word: extends
as a general rule make all fields private and all methods public
it‘s just from the outside, the subobject of the base class is wrapped within the derived-class object. it‘s essential that base-class subobject be initializied correctly and there is only one way to guarantee this: perform the initialization in the constructor by calling the base-class constructor. Java automatically inserts calls to the base-class to the base-class constructor in the derived-class constructor.
class Art {
Art() { print("Art constructor"); }
}
classs Drawing extends Art {
Drawing() { print("Drawing constructor"); }
}
public class Cartoon extends Drawing {
public Cartoon() { print("Cartoon constructor"); }
public static void main(String[] args) {
Cartoon x = new Cartoon();
}
}/*
Art constructor
Drawing constructor
Cartoon constructor
*/
that the construction happens from the base "outward", so the base class is initialized before the drived-class construction can access it.
it there‘s no default base-class constructor, or if you want to call a base-class constructor that has arguments, you must explicitly write a call to the base-class constructor using the super key word and the appropriate argument list, In addition, the call to the base-class constructor must be the first thing you do in the derived-class constructor
some fragment of thinking in java part4
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原文地址：http://www.cnblogs.com/terminator-LLH/p/4910226.html
