oracle习题SQL语句练习

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表（一）Student (学生表)                        

create table student

(

  Sno   varchar2(3) not null,

  Sname   varchar2(8) not null,

  Ssex   varchar2(2) not null,

  Sbirthday   Date,

  Class  varchar2(5)

)

;

comment on column student.Sno

  is ‘学号‘;

comment on column student.Sname

  is ‘学生姓名‘;

comment on column student.Ssex

  is ‘学生性别‘;

comment on column student.Sbirthday

  is ‘学生出生年月‘;

comment on column student.Class

  is ‘学生所在班级‘;

表（二）Course（课程表）

create table Course

(

  Cno   varchar2(5) not null,

  Cname   varchar(10) not null,

  Tno   varchar2(3) not null

)

;

comment on column Course.Cno

  is ‘课程号‘;

comment on column Course.Cname

  is ‘课程名称‘;

comment on column Course.Tno

  is ‘教工编号‘;

alter table Course

  add constraint pk_Course primary key (Cno);

alter table Course

  add constraint fk_Tno foreign key (Tno)

  references Teacher (Tno);

表（三）Score(成绩表)

create table Score

(

  Sno   varchar2(3) not null,

  Cno   varchar2(5) not null,

  Degree Number(4,1)

)

;

comment on column Score.Sno

  is ‘学号‘;

comment on column Score.Cno

  is ‘课程号‘;

comment on column Score.Degree

  is ‘成绩‘;

alter table Score

  add constraint fk_Sno foreign key (Sno)

   references  student (SNO);

  alter table Score

  add constraint fk_Cno foreign key (Cno)

   references  Course (Cno);

表（四）Teacher(教师表)

create table TEACHER

(

  tno       VARCHAR2(3) not null,

  tname     VARCHAR2(4) not null,

  tsex      VARCHAR2(2) not null,

  tbirthday DATE,

  prof      VARCHAR2(6),

  depart    VARCHAR2(10) not null

)

comment on column TEACHER.tno

  is ‘教工编号‘;

comment on column TEACHER.tname

  is ‘教工姓名‘;

comment on column TEACHER.tsex

  is ‘教工性别‘;

comment on column TEACHER.tbirthday

  is ‘教工出生年月‘;

comment on column TEACHER.prof

  is ‘职称‘;

comment on column TEACHER.depart

  is ‘教工所在部门‘;

alter table TEACHER

  add constraint PK_Tno primary key (TNO)

表1-2数据库中的数据

表（一）Student

insert into Student values(‘108‘,‘曾华‘,‘男‘,to_date (‘1977-09-01‘,‘yyyy-mm-dd‘),‘95033‘);

insert into Student values(‘105‘,‘匡明‘,‘男‘,to_date (‘1975-10-02‘,‘yyyy-mm-dd‘),‘95031‘);

insert into Student values(‘107‘,‘王丽‘,‘女‘,to_date (‘1976-01-23‘,‘yyyy-mm-dd‘),‘95033‘);

insert into Student values(‘101‘,‘李军‘,‘男‘,to_date (‘1976-02-20‘,‘yyyy-mm-dd‘),‘95033‘);

insert into Student values(‘109‘,‘王芳‘,‘女‘,to_date (‘1975-02-10‘,‘yyyy-mm-dd‘),‘95031‘);

insert into Student values(‘103‘,‘陆君‘,‘男‘,to_date (‘1974-06-03‘,‘yyyy-mm-dd‘),‘95031‘);

表（二）Course

insert into Course values(‘3-105‘,‘计算机导论‘,‘825‘);

insert into Course values(‘3-245‘   ,‘操作系统‘,‘804‘);

insert into Course values(‘6-166‘   ,‘数字电路‘, ‘856‘);

insert into Course values(‘9-888‘,  ‘高等数学‘,  ‘831‘);

表（三）Score

insert into score values(‘108‘, ‘6-166‘,  ‘81‘);

表（四）Teacher

insert into Teacher values(‘804‘,   ‘李诚‘, ‘男‘,   to_date(‘1958-12-02‘,‘yyyy-mm-dd‘), ‘副教授‘, ‘计算机系‘);

insert into Teacher values(‘856‘,   ‘张旭‘, ‘男‘,   to_date(‘1969-03-12‘,‘yyyy-mm-dd‘), ‘讲师‘, ‘电子工程系‘);

insert into Teacher values(‘825‘,   ‘王萍‘, ‘女‘,   to_date(‘1972-05-05‘,‘yyyy-mm-dd‘), ‘助教‘, ‘计算机系‘);

insert into Teacher values(‘831‘,   ‘刘冰‘, ‘女‘, to_date(‘1977-08-14‘,‘yyyy-mm-dd‘), ‘助教‘, ‘电子工程系‘);

1、 查询Student表中的所有记录的Sname、Ssex和Class列。

select sname,ssex,class from student;

2、 查询教师所有的单位即不重复的Depart列。

select distinct * from student;

3、 查询Student表的所有记录。

select * from Student;

4、 查询Score表中成绩在60到80之间的所有记录。

select * from Score where DEGREE > 60 and DEGREE < 80;

5、 查询Score表中成绩为85，86或88的记录。

select * from Score where DEGREE = 85 or DEGREE = 86 or DEGREE = 88;

6、 查询Student表中“95031”班或性别为“女”的同学记录。

select * from Student where CLASS = 95031 or SSEX = ‘女‘;

7、 以Class降序查询Student表的所有记录。

select * from student order by class desc;

8、 以Cno升序、Degree降序查询Score表的所有记录。

select * from score order by cno asc , degree desc;

9、 查询“95031”班的学生人数。

select class,count(1) as 数量 from student where class =‘95031‘ group by class;

10、 查询Score表中的最高分的学生学号和课程号。（子查询或者排序）

select sno || cno as 学号和课程号 from score order by DEGREE desc;

11、 查询每门课的平均成绩。

select Cno,count(1) as 数量, avg(Degree) as 平均值 from Score group by Cno;

12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。

select Cno,count(1) as 数量, avg(Degree) as 平均值 from Score where cno like‘3%‘ group by Cno having count(cno)>5;

13、查询分数大于70，小于90的Sno列。

select * from Score where Degree between 70 and 90;

14、查询所有学生的Sname、Cno和Degree列。

Select s.sname,c.cno,c.degree from student s , score c where s.sno=c.sno;

15、查询所有学生的Sno、Cname和Degree列。

Select c.sno,q.cname,c.degree from student s , score c,course q where s.sno=c.sno and q.cno=c.cno;

16、查询所有学生的Sname、Cname和Degree列。

Select s.sname,q.cname,c.degree from student s , score c,course q where s.sno=c.sno and q.cno=c.cno;

17、 查询“95033”班学生的平均分。

Select class,avg(degree) as 平均值 from student s,score c where s.sno=c.sno and class = ‘95033‘ group by class ;

18、 假设使用如下命令建立了一个grade表：

create table grade(low  number(3),upp  number (3),rank  char(1))

insert into grade values(90,100,‘A‘);

insert into grade values(80,89,‘B‘);

insert into grade values(70,79,‘C‘);

insert into grade values(60,69,‘D‘);

insert into grade values(0,59,‘E‘);

现查询所有同学的Sno、Cno和rank列。

select s.sno,s.cno,g.rank from score s , grade g where s.Degree between g.low and g.upp;

oracle习题SQL语句练习

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原文地址：http://www.cnblogs.com/name-hanlin/p/4918557.html