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<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title></title> <script src="js/jquery.js"></script> <script> $(function(){ $(‘#btnok‘).bind(‘click‘,function(){ var username = $(‘#username‘).val(); //发送ajax请求 $.ajax({ type:‘post‘, url:‘ajax2.php‘, data:‘username=‘+username, success:function(msg){ alert(msg); } }); }); }); </script> </head> <body> <input type="text" id="username" /> <hr /> <input type="button" id="btnok" value="OK" /> </body> </html>
php里面的代码如下：
<?php $username = $_POST[‘username‘]; echo "hello ".$username;
夺命雷公狗jquery---53--jQuery里的ajax的底层实现POST请求
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原文地址：http://www.cnblogs.com/leigood/p/4922289.html
