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输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则
/* struct ListNode { int val; struct ListNode *next; ListNode(int x) : val(x), next(NULL) { } };*/ class Solution { public: ListNode* Merge(ListNode* pHead1, ListNode* pHead2) { if(pHead1==NULL) return pHead2; if(pHead2==NULL) return pHead1; ListNode* node=new ListNode(NULL); if(pHead1->val<pHead2->val) { node=pHead1; node->next=Merge(pHead1->next,pHead2); } else { node=pHead2; node->next=Merge(pHead1,pHead2->next); } return node; } };
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原文地址:http://www.cnblogs.com/cancangood/p/4951070.html