MinStakc.cpp
#include<iostream>
using namespace std;
#include<stack>
template<class T>
class Stack{
public:
void Push(const T& x){ //入栈
_stack.push(x);
if (_minstack.empty())
_minstack.push(x);
else{
_minstack.push((_minstack.top() > x )? x : _minstack.top());
}
}
void Pop(){ //出栈
_stack.pop();
_minstack.pop();
}
T GetMin(){ //栈的最小值
cout << _minstack.top() << endl;
return _minstack.top();
}
private:
stack<T> _stack;
stack<T> _minstack;
};
void test(){
Stack<int> s;
s.Push(1);
s.Push(2);
s.Push(5);
s.Push(7);
s.Push(8);
s.GetMin();
s.Pop();
s.GetMin();
s.Pop();
s.GetMin();
s.Pop();
}
int main(){
test();
return 0;
}本文出自 “moLova” 博客,请务必保留此出处http://molova.blog.51cto.com/10594266/1711380
c++:实现一个栈,包括入栈、出栈函数以及返回最小值,要求时间复杂度为O(1)
原文地址:http://molova.blog.51cto.com/10594266/1711380