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#!/usr/bin/env python from operator import add, sub from random import randint, choice ops = {‘+‘: add, ‘-‘: sub} MAXTRIES = 2 def doprob(): op = choice(‘+-‘) nums = [ randint(1,10) for i in range(2) ] nums.sort(reverse=True) ans = ops[op](*nums) pr = ‘%d %s %s = ‘ % (nums[0], op, nums[1]) oops = 0 while True: try: if int(raw_input(pr)) == ans:##只有正确作答才跳出循环 print ‘correct‘ break if oops == MAXTRIES:##第二次给出正确答案,但是依然是这道题目 print ‘sorry... the answer is\n%s%d‘ % (pr, ans) else: print ‘incorrect... try again‘ oops += 1 except (KeyboardInterrupt, EOFError, ValueError): print ‘invalid input... try again‘ def main(): while True: doprob() try: opt = raw_input(‘Again? [y] ‘).lower() if opt and opt[0] == ‘n‘: break except (KeyboardInterrupt, EOFError): break if __name__ == ‘__main__‘: main()
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原文地址:http://www.cnblogs.com/paulwinflo/p/4971835.html