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leetcode Swap Nodes in Pairs python

时间:2015-11-25 23:41:42      阅读:363      评论:0      收藏:0      [点我收藏+]

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# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def swapPairs(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        if head == None or head.next == None:
            return head
        dummy=ListNode(0)
        dummy.next=head
        p=dummy
        while p.next and p.next.next:
            tmp=p.next.next
            p.next.next=tmp.next
            tmp.next=p.next
            p.next=tmp
            p=p.next.next
        return dummy.next

 

leetcode Swap Nodes in Pairs python

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原文地址:http://www.cnblogs.com/allenhaozi/p/4996267.html

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