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Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
题目很简单,关键在于终止条件的判断。
使用hashset,把每次需要被判断的n放进去,当有重复的值出现的时候说明会陷入死循环,终止,返回false即可。
参考代码:
public class Solution { public boolean isHappy(int n) { HashSet<Integer> occured = new HashSet<>(); if(n == 1) return true; while(!occured.contains(n)){ occured.add(n); int sum = 0; while(n>0){ sum += (n%10)*(n%10); n /= 10; } if(sum == 1) return true; n = sum; } return false; } }
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原文地址:http://www.cnblogs.com/92sunqing/p/5017783.html