标签:
题意:训练指南P192
分析:主要就是一个在路径压缩的过程中,更新点i到根的距离
#include <bits/stdc++.h> using namespace std; const int N = 2e4 + 5; struct DSU { int rt[N], d[N]; void init(void) { memset (rt, -1, sizeof (rt)); memset (d, 0, sizeof (d)); } int Find(int x) { if (rt[x] != -1) { int root = Find (rt[x]); //先找到根 d[x] += d[rt[x]]; //回溯的过程把距离更新 return rt[x] = root; //路径压缩 } else return x; } void Union(int x, int y) { if (x == y) { d[x] = 0; return ; } else { rt[x] = y; d[x] = abs (x - y) % 1000; } } bool same(int x, int y) { return Find (x) == Find (y); } }dsu; int main(void) { int T; scanf ("%d", &T); while (T--) { int n; scanf ("%d", &n); char str[3]; dsu.init (); int x, y; while (scanf ("%s", str) == 1) { if (str[0] == ‘O‘) break; if (str[0] == ‘E‘) { scanf ("%d", &x); dsu.Find (x); printf ("%d\n", dsu.d[x]); } else { scanf ("%d%d", &x, &y); dsu.Union (x, y); //初始就是到fa的距离 } } } return 0; }
并查集(路径更新) LA 3027 Corporative Network
标签:
原文地址:http://www.cnblogs.com/Running-Time/p/5027140.html