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分两步查询,第一步查询出动态列,第二步使用PIVOT函数。
代码:
List<DataTable> dataTableList = new List<DataTable>(); #region 指标 DataTable dtEvaItemTitle = db.RunTable<Edu_EvaluationRecord>(string.Format(@" select distinct eva.id, eva.name from Edu_EvaluationRecord r left join Edu_QnVolume v on r.queryid=v.id left join Sys_EvaluationItem eva on r.evaitemid=eva.id where v.id={0} order by eva.id", volumeEva.Id)); List<string> evaItemTitleList = new List<string>(); for (int i = 0; i < dtEvaItemTitle.Rows.Count; i++) { evaItemTitleList.Add(string.Format("[{0}]", dtEvaItemTitle.Rows[i]["name"].ToString())); } string evaItemTitles = String.Join(",", evaItemTitleList.ToArray()); string sql = string.Format(@" select * from (select stu.name as 姓名,stu.StuNum as 学号,stu.ExamNum as 考号, case when stu.Sex=‘1‘ then ‘男‘ else ‘女‘ end as 姓别, case when stu.Brothers=‘1‘ then ‘否‘ else ‘是‘ end as 是否独生, stu.EduF as 父亲文化,stu.EduM as 母亲文化, r.score as 分数,eva.Name as 题目 from Edu_EvaluationRecord r left join Edu_Student stu on r.userid=stu.id left join Sys_User u on stu.userid=u.id left join Edu_QnVolume v on r.queryid=v.id left join Sys_EvaluationItem eva on r.evaitemid=eva.id where v.id={0}) p pivot (sum(分数) for 题目 in ({1})) as pvt", volumeEva.Id, evaItemTitles); DataTable dt = db.RunTable<Edu_EvaluationRecord>(sql); dt.TableName = volumeEva.Name; dataTableList.Add(dt); #endregion #region 普通 DataTable dtItemTitle = db.RunTable<Edu_EvaluationRecord>(string.Format(@" select distinct s.id, s.title from edu_qnanswer ans left join Edu_QnSubject s on s.id=ans.subjectid left join Edu_QnVolume v on s.volumeid=v.id where v.id={0} order by s.id", volumeGeneral.Id)); List<string> itemTitleList = new List<string>(); for (int i = 0; i < dtItemTitle.Rows.Count; i++) { itemTitleList.Add(string.Format("[{0}]", dtItemTitle.Rows[i]["title"].ToString())); } string itemTitles = String.Join(",", itemTitleList.ToArray()); sql = string.Format(@" select * from (select stu.name as 姓名,stu.StuNum as 学号,stu.ExamNum as 考号, case when stu.Sex=‘1‘ then ‘男‘ else ‘女‘ end as 姓别, case when stu.Brothers=‘1‘ then ‘否‘ else ‘是‘ end as 是否独生, stu.EduF as 父亲文化,stu.EduM as 母亲文化, ans.Answercontent as 选项,s.Title as 题目 from edu_qnanswer ans left join Sys_User u on ans.answerid=u.id left join Edu_Student stu on stu.userid=u.id left join Edu_QnSubject s on s.id=ans.subjectid left join Edu_QnVolume v on s.volumeid=v.id where v.id={0}) p pivot (max(选项) for 题目 in ({1})) as pvt", volumeGeneral.Id, itemTitles); dt = db.RunTable<Edu_EvaluationRecord>(sql); dt.TableName = volumeGeneral.Name; dataTableList.Add(dt); #endregion
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原文地址:http://www.cnblogs.com/s0611163/p/5052978.html