标签:
不同元素的合集
方法 |
用法 |
范例 |
set() |
过滤掉重复 设置成为集合
|
>>> subset=set([1,1,2,3,4,4,6]) >>> subset set([1, 2, 3, 4, 6]) //集合中剔除了重复的值 这里剔除了1,4 >>> type(subset) //查看subset类型为set集合 <type ‘set‘> |
subset_1 &subset_2 |
求交集
|
>>> subset_1 =set([1,2,3,4,5,6]) >>> subset_2 =set([1,3,4,6]) >>> subset_1 & subset_2 set([1, 3, 4, 6]) |
subset_1 | subset_2 |
求并集
|
>>> subset_1 =set([1,2,3,4,5,6]) >>> subset_2 =set([1,3,6,9,10]) >>> subset_1 | subset_2 set([1, 2, 3, 4, 5, 6, 9, 10]) |
subset_1 ^ subset_2
|
求反交集 |
>>> subset_1 =set([1,2,3,4,5,6]) >>> subset_2 =set([1,3,6,9,10]) >>> subset_1 ^ subset_2 set([2, 4, 5, 9, 10]) |
subset_1 – subset_2 |
剔除所有set2集合中有的值
|
>>> subset_1 =set([1,2,3,4,5,6]) >>> subset_2 =set([1,3,6,9,10]) >>> subset_1 - subset_2 set([2, 4, 5]) |
subset_1.issubset(subset_2) |
判断subset_1是否为subset_2的子集,是则返回 True 否则返回Flase
|
>>> subset_1 = set([1, 2, 3, 4, 5, 6]) >>> subset_2 = set([1, 3, 4]) >>> subset_1.issubset(subset_2) False >>> subset_2.issubset(subset_1) True |
subset_1.issuperset(subset_2) |
判断subset_1是否为subset_2的父集,是则返回 True 否则返回Flase
|
>>> subset_1 = set([1, 2, 3, 4, 5, 6]) >>> subset_2 = set([1, 3, 4]) >>> subset_1.issuperset(subset_2) True |
set.remove(value) |
删除集合set中的value值 |
>>> subset_1 = set([1, 2, 3, 4, 5, 6]) >>> subset_1.remove(4) >>> subset_1 set([1, 2, 3, 5, 6]) |
subset.update(value) |
更新集合将value更新到集合 |
>>> subset = set([1,2,5]) >>> subset.update([5,6,7]) >>> subset set([1, 2, 5, 6, 7]) |
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原文地址:http://www.cnblogs.com/Alanpy/p/5058789.html