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leetcode Count and Say python

时间:2015-12-20 14:39:34      阅读:148      评论:0      收藏:0      [点我收藏+]

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class Solution(object):
    def countAndSay(self, n):
        """
        :type n: int
        :rtype: str
        """
        s=1
        for i in range(2,n+1):
            s=self.count(s)
        return s
    def count(self,s):
        t=‘‘;count=0;curr=#
        for i in s:
            if i != curr:
                if curr != #:
                    t+=str(count)+curr
                curr=i
                count=1
            else:
                count+=1
        t+=str(count)+curr
        return t

@link http://www.cnblogs.com/zuoyuan/p/3781329.html

leetcode Count and Say python

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原文地址:http://www.cnblogs.com/allenhaozi/p/5060774.html

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