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前一阵子,想知道md5的原理查了一下资料,说得基本都一样,最后让我看懂的是这两个链接:
http://blog.csdn.net/qf_study/article/details/2630903
用我的话说一下原理就是这样的:
先定义a、b、c、d四个变量,赋一个初值。
然后把你输入的数据按照每512位分个块,最后的512字节前448字节用部位实现,后64字节存输入的长度;
每个512位的块,分成16个组,每组也就是一个32位的变量,按照一定的算法叠加到a,b,c,d四个变量里;
算法是这样的:a=b+(a+Process P(b,c,d)+M[i]+T[k])<<s),后面的块把结果叠加到前面块的计算结果中(相当于abcd就是个全局变量)
最后算出的a,b,c,d级联到一起,就是一个128位的数,用16进制表示每个位,就是一个长度为32的字符串,也就是最终的结果;
http://www.cnblogs.com/ruihong/archive/2012/10/24/2736727.html (如果转载请加注源作者的链接)
经过修改之后,可以编译使用了,为了方便以后引用,记录如下:
md5.h
#ifndef _CMD5_H #define _CMD5_H //#pragma warning(disable:4786) #include <string> using namespace std; /*! * Manage CMD5. */ class CMD5 { private: #define uint8 unsigned char #define uint32 unsigned long int struct md5_context { uint32 total[2]; uint32 state[4]; uint8 buffer[64]; }; void md5_starts( struct md5_context *ctx ); void md5_process( struct md5_context *ctx, uint8 data[64] ); void md5_update( struct md5_context *ctx, uint8 *input, uint32 length ); void md5_finish( struct md5_context *ctx, uint8 digest[16] ); public: //! construct a CMD5 from any buffer void GenerateMD5(unsigned char* buffer,int bufferlen); //! construct a CMD5 CMD5(); //! construct a md5src from char * CMD5(const char * md5src); //! construct a CMD5 from a 16 bytes md5 CMD5(unsigned long* md5src); //! add a other md5 CMD5 operator +(CMD5 adder); //! just if equal bool operator ==(CMD5 cmper); //! give the value from equer // void operator =(CMD5 equer); //! to a string string ToString(); unsigned long m_data[4]; }; #endif /* md5.h */
md5.cpp
/* * RFC 1321 compliant CMD5 implementation, * by Christophe Devine <devine@cr0.net>; * this program is licensed under the GPL. */ #include "md5.h" #include <stdio.h> #include <stdlib.h> #include <string.h> #define GET_UINT32(n,b,i) \ { (n) = (uint32) ((uint8 *) b)[(i)] | (((uint32) ((uint8 *) b)[(i)+1]) << 8) | (((uint32) ((uint8 *) b)[(i)+2]) << 16) | (((uint32) ((uint8 *) b)[(i)+3]) << 24); } #define PUT_UINT32(n,b,i) \ { (((uint8 *) b)[(i)] ) = (uint8) (((n) ) & 0xFF); (((uint8 *) b)[(i)+1]) = (uint8) (((n) >> 8) & 0xFF); (((uint8 *) b)[(i)+2]) = (uint8) (((n) >> 16) & 0xFF); (((uint8 *) b)[(i)+3]) = (uint8) (((n) >> 24) & 0xFF); } //extern pthread_mutex_t mutexMemory; void CMD5::md5_starts( struct md5_context *ctx ) { ctx->total[0] = 0; ctx->total[1] = 0; ctx->state[0] = 0x67452301; ctx->state[1] = 0xEFCDAB89; ctx->state[2] = 0x98BADCFE; ctx->state[3] = 0x10325476; } void CMD5::md5_process( struct md5_context *ctx, uint8 data[64] ) { uint32 A, B, C, D, X[16]; GET_UINT32( X[0], data, 0 ); GET_UINT32( X[1], data, 4 ); GET_UINT32( X[2], data, 8 ); GET_UINT32( X[3], data, 12 ); GET_UINT32( X[4], data, 16 ); GET_UINT32( X[5], data, 20 ); GET_UINT32( X[6], data, 24 ); GET_UINT32( X[7], data, 28 ); GET_UINT32( X[8], data, 32 ); GET_UINT32( X[9], data, 36 ); GET_UINT32( X[10], data, 40 ); GET_UINT32( X[11], data, 44 ); GET_UINT32( X[12], data, 48 ); GET_UINT32( X[13], data, 52 ); GET_UINT32( X[14], data, 56 ); GET_UINT32( X[15], data, 60 ); #define S(x,n) ((x << n) | ((x & 0xFFFFFFFF) >> (32 - n))) #define P(a,b,c,d,k,s,t) \ { a += F(b,c,d) + X[k] + t; a = S(a,s) + b; } A = ctx->state[0]; B = ctx->state[1]; C = ctx->state[2]; D = ctx->state[3]; #define F(x,y,z) (z ^ (x & (y ^ z))) P( A, B, C, D, 0, 7, 0xD76AA478 ); P( D, A, B, C, 1, 12, 0xE8C7B756 ); P( C, D, A, B, 2, 17, 0x242070DB ); P( B, C, D, A, 3, 22, 0xC1BDCEEE ); P( A, B, C, D, 4, 7, 0xF57C0FAF ); P( D, A, B, C, 5, 12, 0x4787C62A ); P( C, D, A, B, 6, 17, 0xA8304613 ); P( B, C, D, A, 7, 22, 0xFD469501 ); P( A, B, C, D, 8, 7, 0x698098D8 ); P( D, A, B, C, 9, 12, 0x8B44F7AF ); P( C, D, A, B, 10, 17, 0xFFFF5BB1 ); P( B, C, D, A, 11, 22, 0x895CD7BE ); P( A, B, C, D, 12, 7, 0x6B901122 ); P( D, A, B, C, 13, 12, 0xFD987193 ); P( C, D, A, B, 14, 17, 0xA679438E ); P( B, C, D, A, 15, 22, 0x49B40821 ); #undef F #define F(x,y,z) (y ^ (z & (x ^ y))) P( A, B, C, D, 1, 5, 0xF61E2562 ); P( D, A, B, C, 6, 9, 0xC040B340 ); P( C, D, A, B, 11, 14, 0x265E5A51 ); P( B, C, D, A, 0, 20, 0xE9B6C7AA ); P( A, B, C, D, 5, 5, 0xD62F105D ); P( D, A, B, C, 10, 9, 0x02441453 ); P( C, D, A, B, 15, 14, 0xD8A1E681 ); P( B, C, D, A, 4, 20, 0xE7D3FBC8 ); P( A, B, C, D, 9, 5, 0x21E1CDE6 ); P( D, A, B, C, 14, 9, 0xC33707D6 ); P( C, D, A, B, 3, 14, 0xF4D50D87 ); P( B, C, D, A, 8, 20, 0x455A14ED ); P( A, B, C, D, 13, 5, 0xA9E3E905 ); P( D, A, B, C, 2, 9, 0xFCEFA3F8 ); P( C, D, A, B, 7, 14, 0x676F02D9 ); P( B, C, D, A, 12, 20, 0x8D2A4C8A ); #undef F #define F(x,y,z) (x ^ y ^ z) P( A, B, C, D, 5, 4, 0xFFFA3942 ); P( D, A, B, C, 8, 11, 0x8771F681 ); P( C, D, A, B, 11, 16, 0x6D9D6122 ); P( B, C, D, A, 14, 23, 0xFDE5380C ); P( A, B, C, D, 1, 4, 0xA4BEEA44 ); P( D, A, B, C, 4, 11, 0x4BDECFA9 ); P( C, D, A, B, 7, 16, 0xF6BB4B60 ); P( B, C, D, A, 10, 23, 0xBEBFBC70 ); P( A, B, C, D, 13, 4, 0x289B7EC6 ); P( D, A, B, C, 0, 11, 0xEAA127FA ); P( C, D, A, B, 3, 16, 0xD4EF3085 ); P( B, C, D, A, 6, 23, 0x04881D05 ); P( A, B, C, D, 9, 4, 0xD9D4D039 ); P( D, A, B, C, 12, 11, 0xE6DB99E5 ); P( C, D, A, B, 15, 16, 0x1FA27CF8 ); P( B, C, D, A, 2, 23, 0xC4AC5665 ); #undef F #define F(x,y,z) (y ^ (x | ~z)) P( A, B, C, D, 0, 6, 0xF4292244 ); P( D, A, B, C, 7, 10, 0x432AFF97 ); P( C, D, A, B, 14, 15, 0xAB9423A7 ); P( B, C, D, A, 5, 21, 0xFC93A039 ); P( A, B, C, D, 12, 6, 0x655B59C3 ); P( D, A, B, C, 3, 10, 0x8F0CCC92 ); P( C, D, A, B, 10, 15, 0xFFEFF47D ); P( B, C, D, A, 1, 21, 0x85845DD1 ); P( A, B, C, D, 8, 6, 0x6FA87E4F ); P( D, A, B, C, 15, 10, 0xFE2CE6E0 ); P( C, D, A, B, 6, 15, 0xA3014314 ); P( B, C, D, A, 13, 21, 0x4E0811A1 ); P( A, B, C, D, 4, 6, 0xF7537E82 ); P( D, A, B, C, 11, 10, 0xBD3AF235 ); P( C, D, A, B, 2, 15, 0x2AD7D2BB ); P( B, C, D, A, 9, 21, 0xEB86D391 ); #undef F ctx->state[0] += A; ctx->state[1] += B; ctx->state[2] += C; ctx->state[3] += D; } void CMD5::md5_update( struct md5_context *ctx, uint8 *input, uint32 length ) { uint32 left, fill; if( ! length ) return; left = ( ctx->total[0] >> 3 ) & 0x3F; fill = 64 - left; ctx->total[0] += length << 3; ctx->total[1] += length >> 29; ctx->total[0] &= 0xFFFFFFFF; ctx->total[1] += ctx->total[0] < length << 3; if( left && length >= fill ) { memcpy( (void *) (ctx->buffer + left), (void *) input, fill ); md5_process( ctx, ctx->buffer ); length -= fill; input += fill; left = 0; } while( length >= 64 ) { md5_process( ctx, input ); length -= 64; input += 64; } if( length ) { memcpy( (void *) (ctx->buffer + left), (void *) input, length ); } } static uint8 md5_padding[64] = { 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; void CMD5::md5_finish( struct md5_context *ctx, uint8 digest[16] ) { uint32 last, padn; uint8 msglen[8]; PUT_UINT32( ctx->total[0], msglen, 0 ); PUT_UINT32( ctx->total[1], msglen, 4 ); last = ( ctx->total[0] >> 3 ) & 0x3F; padn = ( last < 56 ) ? ( 56 - last ) : ( 120 - last ); md5_update( ctx, md5_padding, padn ); md5_update( ctx, msglen, 8 ); PUT_UINT32( ctx->state[0], digest, 0 ); PUT_UINT32( ctx->state[1], digest, 4 ); PUT_UINT32( ctx->state[2], digest, 8 ); PUT_UINT32( ctx->state[3], digest, 12 ); } void CMD5::GenerateMD5(unsigned char* buffer,int bufferlen) { struct md5_context context; md5_starts (&context); md5_update (&context, buffer, bufferlen); md5_finish (&context,(unsigned char*)m_data); } CMD5::CMD5() { for(int i=0;i<4;i++) m_data[i]=0; } CMD5::CMD5(unsigned long* md5src) { memcpy(m_data,md5src,16); } int _httoi(const char *value) { struct CHexMap { char chr; int value; }; const int HexMapL = 16; CHexMap HexMap[HexMapL] = { {‘0‘, 0}, {‘1‘, 1}, {‘2‘, 2}, {‘3‘, 3}, {‘4‘, 4}, {‘5‘, 5}, {‘6‘, 6}, {‘7‘, 7}, {‘8‘, 8}, {‘9‘, 9}, {‘a‘, 10}, {‘b‘, 11}, {‘c‘, 12}, {‘d‘, 13}, {‘e‘, 14}, {‘f‘, 15} }; //pthread_mutex_lock(&mutexMemory); char *mstr = strdup(value); //pthread_mutex_unlock(&mutexMemory); char *s = mstr; int result = 0; if (*s == ‘0‘ && *(s + 1) == ‘X‘) s += 2; bool firsttime = true; while (*s != ‘/0‘) { bool found = false; for (int i = 0; i < HexMapL; i++) { if (*s == HexMap[i].chr) { if (!firsttime) result <<= 4; result |= HexMap[i].value; found = true; break; } } if (!found) break; s++; firsttime = false; } //pthread_mutex_lock(&mutexMemory); free(mstr); //pthread_mutex_unlock(&mutexMemory); return result; } CMD5::CMD5(const char* md5src) { if (strcmp(md5src,"")==0) { for(int i=0;i<4;i++) m_data[i]=0; return; } for(int j = 0; j < 16; j++ ) { char buf[10]; strncpy(buf,md5src,2); md5src+=2; ((unsigned char*)m_data)[j] = _httoi(buf); } } CMD5 CMD5::operator +(CMD5 adder) { unsigned long m_newdata[4]; for(int i=0;i<4;i++) m_newdata[i]=m_data[i]^(adder.m_data[i]); return CMD5(m_newdata); } bool CMD5::operator ==(CMD5 cmper) { return (memcmp(cmper.m_data ,m_data,16)==0); } //void CMD5::operator =(CMD5 equer) //{ // memcpy(m_data,equer.m_data ,16); //} string CMD5::ToString() { char output[33]; for(int j = 0; j < 16; j++ ) { sprintf( output + j * 2, "%02x", ((unsigned char*)m_data)[j]); } return string(output); }
main.cpp
#include <iostream> #include "md5.h" using namespace std; int main() { const char *text = "hello world"; const char *text1 = "hello "; const char *text2 = "world"; CMD5 iMD5; iMD5.GenerateMD5((unsigned char*)text, strlen(text) ); std::string result = iMD5.ToString(); cout<<result<<endl; }
Makefile
COMPILER=g++ executemain : main.o md5.o $(COMPILER) -o executemain main.o md5.o main.o : main.cpp md5.h $(COMPILER) -g -c main.cpp md5.o : md5.h md5.cpp $(COMPILER) -g -c md5.cpp clean : rm -f executemain main.o md5.o
源码中只给md5传了一个字符数组,万一是大文件怎么办?
看懂了原理,应该不难理解,都是分成512个位的块叠加,用数组多传几次是一样的效果,只是源码中把主要函数设置为私有变量,如果需要自己封装一下也可以实现,只是给大家引用一个CSDN大神的解法:http://bbs.csdn.net/topics/230085330提供个思路吧
$ cat t2.c; gcc -o t2 t2.c `pkg-config openssl --cflags --libs`; ./t2 /***************************************************************/ #include <stdio.h> #include <openssl/md5.h> #include <openssl/rand.h> typedef unsigned char byte; #define INPUT_LEN (1024+123) void test1( byte* input , int len , int l1 ) { int i; byte md5[16]; MD5_CTX ctx; MD5_Init( &ctx ); for( ;len >= l1; input += l1 , len -= l1 ) MD5_Update( &ctx , input , l1 ); if( len ) MD5_Update( &ctx , input , len ); MD5_Final( md5 , &ctx ); for( i = 0; i < 16; ++i ) printf( "%02X " , md5[i] ); printf( " : %d\n" , l1 ); } int main() { int l1; byte input[INPUT_LEN]; RAND_bytes( input , sizeof( input ) ); for( l1 = 1; l1 <= INPUT_LEN; l1 <<= 1 ) test1( input , sizeof( input ) , l1 ); return 0; } /***************************************************************/ AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 1 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 2 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 4 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 8 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 16 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 32 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 64 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 128 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 256 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 512 AD 84 BB AF 9C E9 5A DD 7D CB 3A 3F C8 E1 63 03 : 1024
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原文地址:http://www.cnblogs.com/bugutian/p/5071016.html