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Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1 / 2 2 / \ / 3 4 4 3
But the following is not:
1 / 2 2 \ 3 3https://leetcode.com/problems/symmetric-tree/
1 /** 2 * Definition for a binary tree node. 3 * function TreeNode(val) { 4 * this.val = val; 5 * this.left = this.right = null; 6 * } 7 */ 8 /** 9 * @param {TreeNode} root 10 * @return {boolean} 11 */ 12 var isSymmetric = function(root) { 13 if(root === null) return true; 14 return symmetric(root.left, root.right); 15 16 function symmetric(leftNode, rightNode){ 17 if(leftNode === null && rightNode === null) return true; 18 if(leftNode !== null && rightNode !== null){ 19 if(leftNode.val !== rightNode.val) return false; 20 return symmetric(leftNode.left, rightNode.right) 21 && symmetric(leftNode.right, rightNode.left); 22 }else{ 23 return false; 24 } 25 } 26 };
[LeetCode][JavaScript]Symmetric Tree
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原文地址:http://www.cnblogs.com/Liok3187/p/5092480.html