oracle 开发 第2章 查询

select customer_id,first_name,last_name,dob,phone from customers;
select * from customers;

select * from customers where customer_id =2;

select rowid,customer_id from customers;

select rownum,customer_id,first_name,last_name from customers;
select rownum,customer_id,first_name,last_name from customers where customer_id = 3;

select 2*6 from dual;
select 10*12/3-1 from dual;
select 10*(12/3-1) from dual;

select to_date(‘2012/7/25‘,‘yyyy/mm/dd‘) + 1 from dual;
select * from dual;
select to_date(‘2012/8/2‘,‘yyyy/mm/dd‘) - 3 from dual;

select name,price + 2 from products;
select name,price*3 +1 from products;

select price*2 double_price from products;
select price*2 "double price" from products;
select 10*(12/3-1) as "computation" from dual;

select first_name||‘ ‘||last_name as "customers name" from customers;

select * from customers;
select customer_id,first_name,last_name,dob from customers where dob is null;
select customer_id,first_name,last_name,phone from customers where phone is null;
select customer_id,first_name,last_name,nvl(phone,‘unkown phone number‘) as phone_number from customers;
select customer_id,first_name,last_name,nvl(dob,to_date(‘2000/01/01‘)) as dob from customers;

select customer_id from purchases;
select distinct customer_id from purchases;

select * from customers where customer_id <> 2;
select product_id,name from products where product_id < 8;
select rownum,product_id,name from products where rownum <= 3;
select * from customers where customer_id > any(2,3,4);
select * from customers where customer_id > all(2,3,4);

select * from customers where first_name like ‘_o%‘;            --下划线匹配一个字符，百分号匹配任意多个字符
select * from customers where first_name not like ‘_o%‘;
select name from promotions where name like ‘%\%%‘ escape ‘\‘;  --\是转义字符，告诉数据库如何区分要搜索的字符和通配符

select * from customers where customer_id in (2,3,5);
select * from customers where customer_id not in (2,3,5);
select * from customers where customer_id not in (2,3,5,null);    --列表中包含null值时，not in 不返回值

select * from customers where customer_id between 1 and 3;        --区间是闭区间
select * from customers where customer_id not between 1 and 3;    --not between检索2个开区间

select * from customers 
where dob > to_date(‘1970/01/01‘,‘yyyy/mm/dd‘) and customer_id > 3;

select * from customers
where dob > to_date(‘1970/01/01‘,‘yyyy/mm/dd‘) or customer_id > 3;

select * from customers 
where dob > to_date(‘1970/01/01‘,‘yyyy/mm/dd‘) or customer_id < 2 and phone like ‘%1211‘;        --比较优于and，and优先于or

select * from customers 
where dob > to_date(‘1970/01/01‘,‘yyyy/mm/dd‘) or (customer_id < 2 and phone like ‘%1211‘);

select * from customers order by last_name;            --默认升序
select * from customers order by first_name asc,last_name desc;
select customer_id,first_name,last_name from customers order by 1;    --根据列的位置序号排序

select name,product_type_id from products where product_id = 3;
select name from product_types where product_type_id = 2;

select products.name,product_types.name 
from products,product_types 
where products.product_type_id = product_types.product_type_id 
and products.product_id = 3;            --查询product_id为3的产品的名称及类型

select products.name,product_types.name
from products,product_types
where products.product_type_id = product_types.product_type_id
order by products.name;                    --查询所有产品的名称及类型

select p.name,pt.name from products p,product_types pt
where p.product_type_id = pt.product_type_id
order by p.name;

select pt.product_type_id,p.product_id from product_types pt,products p;

select c.first_name,c.last_name,p.name as prodcut,pt.name as type
from customers c,purchases pr,products p,product_types pt
where c.customer_id = pr.customer_id
and p.product_id = pr.product_id
and p.product_type_id = pt.product_type_id
order by p.name;                --查询顾客购买信息

select * from salary_grades;    --查询员工工资等级
select * from employees;        --查询员工工资
select e.first_name,e.last_name,e.title,e.salary,sg.salary_grade_id
from employees e,salary_grades sg
where e.salary between sg.low_salary and sg.high_salary
order by salary_grade_id;        --查询员工的工资和工资等级

select p.name,pt.name
from products p,product_types pt
where p.product_type_id = pt.product_type_id (+)
order by p.name;

select p.name,pt.name
from products p left outer join product_types pt
on p.product_type_id = pt.product_type_id
order by p.name;                --SQL/92标准

select p.name,pt.name
from products p left outer join product_types pt
using (product_type_id)
order by p.name;                --SQL/92标准

select p.name,pt.name
from products p,product_types pt
where p.product_type_id (+) = pt.product_type_id
order by p.name;

select p.name,pt.name
from products p right outer join product_types pt
on p.product_type_id = pt.product_type_id
order by p.name;                --SQL/92标准

select p.name,pt.name
from products p right outer join product_types pt
using (product_type_id)
order by p.name;                --SQL/92标准

select * from employees;

select w.first_name ||‘ ‘||w.last_name || ‘works for ‘|| m.first_name ||‘ ‘ || m.last_name
from employees w,employees m
where w.manager_id = m.employee_id
order by w.first_name;        --查询每个雇员及其管理者的名字

select w.last_name || ‘works for ‘|| nvl(m.last_name,‘the shareholders‘)
from employees w,employees m
where w.manager_id = m.employee_id (+)
order by w.last_name;        --查询每个雇员及其管理者名字，包括CEO

select p.name,pt.name 
from products p,product_types pt
where p.product_type_id = pt.product_type_id
order by p.name;            --where子句，SQL/86标准

select p.name,pt.name 
from products p inner join product_types pt
on p.product_type_id = pt.product_type_id
order by p.name;            --join子句，SQL/92标准

select p.name,pt.name
from products p inner join product_types pt
using (product_type_id)
order by p.name;            --using子句，等值连接，且连接列同名

select p.name,pt.name,product_type_id 
from products p inner join product_types pt
using (product_type_id)
order by p.name;            --using子句引用列，不加表名或别名

select e.first_name,e.last_name,e.title,e.salary,sg.salary_grade_id
from employees e,salary_grades sg
where e.salary between sg.low_salary and sg.high_salary
order by salary_grade_id;

select e.first_name,e.last_name,e.title,e.salary,sg.salary_grade_id
from employees e inner join salary_grades sg
on e.salary between sg.low_salary and sg.high_salary
order by salary_grade_id;

select c.first_name,c.last_name,p.name as prodcut,pt.name as type
from customers c,purchases pr,products p,product_types pt
where c.customer_id = pr.customer_id
and p.product_id = pr.product_id
and p.product_type_id = pt.product_type_id
order by p.name;        --where子句，SQL/86标准

select c.first_name,c.last_name,p.name as prodcut,pt.name as type
from customers c inner join purchases pr
using (customer_id)
inner join products p
using (product_id)
inner join product_types pt
using (product_type_id)
order by p.name;        --join子句，SQL/92标准