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1. 错误方式
#这里初始化一个dict >>> d = {‘a‘:1, ‘b‘:0, ‘c‘:1, ‘d‘:0} #本意是遍历dict,发现元素的值是0的话,就删掉 >>> for k in d: ... if d[k] == 0: ... del(d[k]) ... Traceback (most recent call last): File "<stdin>", line 1, in <module> RuntimeError: dictionary changed size during iteration #结果抛出异常了,两个0的元素,也只删掉一个。 >>> d {‘a‘: 1, ‘c‘: 1, ‘d‘: 0} >>> d = {‘a‘:1, ‘b‘:0, ‘c‘:1, ‘d‘:0} #d.keys() 是一个下标的数组 >>> d.keys() [‘a‘, ‘c‘, ‘b‘, ‘d‘] #这样遍历,就没问题了,因为其实其实这里遍历的是d.keys()这个list常量。 >>> for k in d.keys(): ... if d[k] == 0: ... del(d[k]) ... >>> d {‘a‘: 1, ‘c‘: 1} #结果也是对的 >>>
2.正确方式
>>> a = [1,2,0,3,0,4,5] >>> a = [i for i in alist if i != 0] >>> a [1, 2, 3, 4, 5]
>>> d = {‘a‘:1, ‘b‘:0, ‘c‘:1, ‘d‘:0} >>> d = {k:v for k,v in d.iteritems() if v !=0 } >>> d {‘a‘:1,‘c‘:1‘}
python : dictionary changed size during iteration
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原文地址:http://www.cnblogs.com/yuyutianxia/p/5106386.html