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public class Test { public static void main(String[] args) { int arr1[]={1,3,5,7,9}; int arr2[]={2,4,6,8,10}; memeryArray(arr1, arr2); } public static void memeryArray(int arr1[],int arr2[]){ int i=0,j = 0,k = 0; int arr3[]=new int[arr1.length+arr2.length]; while(i<arr1.length&&j<arr2.length){ if(arr1[i]<arr2[j]) arr3[k++]=arr1[i++]; else arr3[k++]=arr2[j++]; } while(i<arr1.length) arr3[k++]=arr1[i++]; while(j<arr2.length) arr3[k++]=arr2[j++]; for (int i1 = 0; i1 < arr3.length; i1++) { System.out.println(arr3[i1]); } } }
上面就是对两个有序数组进行归并排序时间复杂度是常数级,所以值得借鉴。于是产生了更加牛逼的归并排序。可以将A,B组各自再分成二组。依次类推,当分出来的小组只有一个数据时,可以认为这个小组组内已经达到了有序,然后再合并相邻的二个小组就可以了。这样通过先递归的分解数列,再合并数列就完成了归并排序。
public class MergeSort { ////将有二个有序数列a[first...mid]和a[mid...last]合并。 void mergearray(int a[], int first, int mid, int last, int temp[]) { int i = first, j = mid + 1; int m = mid, n = last; int k = 0; while (i <= m && j <= n) { if (a[i] <= a[j]) temp[k++] = a[i++]; else temp[k++] = a[j++]; } while (i <= m) temp[k++] = a[i++]; while (j <= n) temp[k++] = a[j++]; //将合并序列复制到原始序列中 for (i = 0; i < k; i++) a[first + i] = temp[i]; } void mergesort(int a[], int first, int last, int temp[]) { if (first < last) { int mid = (first + last) / 2; mergesort(a, first, mid, temp); //左边有序 mergesort(a, mid + 1, last, temp); //右边有序 mergearray(a, first, mid, last, temp); //再将二个有序数列合并 } } }
public class Test { public static void main(String[] args){ int arr[]={1,4,2,54,3,0,9}; int temp[]=new int[arr.length]; MergeSort merge=new MergeSort(); merge.mergesort(arr, 0, arr.length-1, temp); for (int i = 0; i < temp.length; i++) { System.out.print(temp[i]+" "); } } }
归并排序与初始序列无关,时间复杂度位
平均是O(n㏒2n) 最好O(n㏒2n) 最坏O(n㏒2n)
空间复杂度O(n)
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原文地址:http://www.cnblogs.com/clarencezzh/p/5117333.html