码迷,mamicode.com
首页 > 编程语言 > 详细

Java [Leetcode 110]Balanced Binary Tree

时间:2016-01-12 18:05:51      阅读:166      评论:0      收藏:0      [点我收藏+]

标签:

题目描述:

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

解题思路:

递归法解题。

代码如下:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean isBalanced(TreeNode root) {
    	if(root == null)
    		return true;
    	else{
    		if(Math.abs(getHeight(root.left) - getHeight(root.right)) > 1)
    			return false;
    		else 
    			return isBalanced(root.left) && isBalanced(root.right);
    	}
    }

    public int getHeight(TreeNode root){
    	if(root == null)
    		return 0;
    	else return 1 + Math.max(getHeight(root.left), getHeight(root.right));
    }
}

  

Java [Leetcode 110]Balanced Binary Tree

标签:

原文地址:http://www.cnblogs.com/zihaowang/p/5125144.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!