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这两个函数,是偏移量函数,其用途是:可以查出同一字段下一个值或上一个值。
lead(col_name,num,flag) col_name是列名;num是取向下第几个值;flag是一个标志,也就是如果向下第几个值是空值的话就取flag; 例如lead(login_time,1,null)这个是向下取一个值,如果这个值为空则按空算,当然也可以用其他值替换。 lag(col_name,num,flag) 和lead类似,col_name是列名;num是取向上第几个值;flag是一个标志,也就是如果向上第几个值是空值的话就取flag; 例如lag(login_time,1,null)这个是向上取一个值,如果这个值为空则按空算,当然也可以用其他值替换。
举个例子:有一个表tmp_test(u_id,login_time)查一下这个表中连续7天都有登录机器的人是谁? 造下数据: create table tmp_test(u_id number,login_time date);
insert into tmp_test select 1 rn,sysdate + rownum as login_time from dual connect by level <=8 union select 2 rn,sysdate + rownum as login_time from dual connect by level <=3 union select 3 rn,sysdate + rownum as login_time from dual connect by level <=2 union select 2 rn,sysdate + rownum+4 as login_time from dual connect by level <=5; commit;
然后造几条重复数据: insert into tmp_test select 1 rn,sysdate + rownum as login_time from dual connect by level <=3;
查下数据: select * from tmp_test; U_ID LOGIN_TIME ---------- ----------- 1 2012/3/8 6:33:24 1 2012/3/9 6:33:24 1 2012/3/10 6:33:24 1 2012/3/11 6:33:24 1 2012/3/12 6:33:24 1 2012/3/13 6:33:24 1 2012/3/14 6:33:24 1 2012/3/15 6:33:24 2 2012/3/8 6:33:24 2 2012/3/9 6:33:24 2 2012/3/10 6:33:24 2 2012/3/12 6:33:24 2 2012/3/13 6:33:24 2 2012/3/14 6:33:24 2 2012/3/15 6:33:24 2 2012/3/16 6:33:24 3 2012/3/8 6:33:24 3 2012/3/9 6:33:24 1 2012/3/8 6:37:35 1 2012/3/9 6:37:35 1 2012/3/10 6:37:35
从上面数据看出其实只有u_id=1满足条件,那么怎么用sql实现呢? SQL> select distinct u_id 2 from (select u_id, 3 login_time last_login_time, 4 lead(login_time, 6) over(partition by u_id order by u_id, login_time) next_login_time 5 from (select distinct u_id, trunc(login_time) login_time 6 from tmp_test)) 7 where next_login_time - last_login_time = 6; U_ID ---------- 1
ok,就是这个结果。其实用lag也可以实现相同结果,写法如下:
select distinct u_id from (select u_id, login_time last_login_time, lag(login_time, 6) over(partition by u_id order by u_id, login_time) next_login_time from (select distinct u_id, trunc(login_time) login_time from tmp_test)) where last_login_time - next_login_time = 6;
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原文地址:http://www.cnblogs.com/wjwen/p/5135194.html