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题目描述：
Given a binary tree, return the level order traversal of its nodes‘ values. (ie, from left to right, level by level).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ 9 20
/ 15 7
return its level order traversal as:
[ [3], [9,20], [15,7] ]
解题思路：
运用广度优先搜索方法，同http://www.cnblogs.com/zihaowang/p/5149745.html类似。
代码如下：
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> result = new LinkedList<List<Integer>>();
Queue<TreeNode> queue = new LinkedList<TreeNode>();
if(root == null)
return result;
queue.offer(root);
while(!queue.isEmpty()){
int m = queue.size();
List<Integer> list = new LinkedList<Integer>();
for(int i = 0; i < m; i++){
if(queue.peek().left != null)
queue.offer(queue.peek().left);
if(queue.peek().right != null)
queue.offer(queue.peek().right);
list.add(queue.poll().val);
}
result.add(new LinkedList<Integer>(list));
}
return result;
}
}
Java [Leetcode 102]Binary Tree Level Order Traversal
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原文地址：http://www.cnblogs.com/zihaowang/p/5159022.html
