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principal = 1000
rate = 0.05
numyears = 5
year = 1
while year <= numyears:
principal = principal * ( 1 + rate )
print( year , principal)
year += 1
#输出:
python express.py
(1, 1050.0)
(2, 1102.5)
(3, 1157.625)
(4, 1215.5062500000001)
(5, 1276.2815625000003)
#将 print( year , principal)替换成 print( format(year,‘3d‘),format(principal,‘0.2f‘))
#输出
python express.py
(‘ 1‘, ‘1050.00‘)
(‘ 2‘, ‘1102.50‘)
(‘ 3‘, ‘1157.62‘)
(‘ 4‘, ‘1215.51‘)
(‘ 5‘, ‘1276.28‘)
format(‘要输出的内容‘,‘格式‘)
#还可以
#将 print( year , principal)替换成 print(‘{0:3d} {1:0.2f}‘.format(year,principal))
python express.py
1 1050.00
2 1102.50
3 1157.62
4 1215.51
5 1276.28#print(‘{0:3d} {1:0.2f}‘.format(year,principal)):号前面的0表示year第一个位置,:号前面的1表示princpal第二个位置,:号后面的代表格式
#字典格式输出
List = {‘Name‘: ‘xiaowei‘, ‘Age‘: 23, ‘Job‘: ‘Python‘}
print(‘Name: {0[Name]:s}; Age: {0[Age]:d}; ‘‘Job: {0[Job]:s}‘.format(List))
#输出
#Name: xiaowei; Age: 23; Job: Python
##################################################################
#此外还可以
print(‘{year} {principal}‘.format(year=12,principal=3))
#结果
#python express.py
#12 3
#############################################################
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原文地址:http://www.cnblogs.com/zhuweiblog/p/5162967.html