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if answer==nil{ //计算方程的解 var p0:Double=leftbound! var p1:Double=rightbound! var q0:Double = comresult(p0) var q1:Double = comresult(p1) var p:Double=0 var q:Double=0 for i in 2...trycount{ p = secantcompresult(p0, myp1:p1) if abs(p-p1) < accuracy { answer=p0 break } q = comresult(p) if q * q1 < 0 { p0=p1 q0=q1 } p1=p q1=q } } if let ans=answer{ //方程有解 result.stringValue="解:"+String(stringInterpolationSegment: ans)+" " result.stringValue += "解代入方程的值:"+String(stringInterpolationSegment:comresult(ans)) }
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原文地址:http://blog.csdn.net/myhaspl/article/details/50614014