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题目描述：
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 andnums2 are m and n respectively.
解题思路：
设置两个指针，从两个数组的最后位置开始判断大小。
代码如下：
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m - 1, j = n - 1, k = m + n - 1;
while(k >= 0){
if(i >= 0 && j >= 0){
if(nums1[i] > nums2[j]){
nums1[k--] = nums1[i--];
} else {
nums1[k--] = nums2[j--];
}
} else if(i < 0){
nums1[k--] = nums2[j--];
} else {
nums1[k--] = nums1[i--];
}
}
}
}
Java [Leetcode 88]CMerge Sorted Array
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原文地址：http://www.cnblogs.com/zihaowang/p/5183030.html
