举一反三，取buglist中的url

# -*- coding: utf-8 -*-
import re,xlwt,xlrd
from xlutils.copy import copy
def reinfourl(test):
    m = re.search(r"[a-zA-z]+://[^\s]*",test)
    if m :
        return m.group(0)
    else:
        return "no url"
    
oldex = xlrd.open_workbook(r"buglist218.xls")
oldsh = oldex.sheet_by_index(0)
nrows = oldsh.nrows
newex  = copy(oldex)
newsh = newex.get_sheet(0)
for i in range(1,nrows):
    test = oldsh.cell(i,3).value
    newsh.write(i,4,reinfourl(test))
    print "#%d"%i,reinfourl(test)
newex.save(r"buglist218.xls")