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You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 –> 8
#include <gtest/gtest.h> using namespace std; struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* result = 0; ListNode* current = 0; int carry = 0; while (l1 != NULL || l2 != NULL) { int value = 0; if (l1 != NULL) { value += l1->val; l1 = l1->next; } if (l2 != NULL) { value += l2->val; l2 = l2->next; } if (current == NULL) { current = result = new ListNode(value % 10); carry = value / 10; } else { current->next = new ListNode((value + carry) % 10); carry = (value + carry) / 10; current = current->next; } } if (carry) { if (current == NULL) { current = result = new ListNode(carry); } else { current->next = new ListNode(carry); current = current->next; } } return result; } TEST(Pratices, tAddTwoNumbers) { // (2 -> 4 -> 3) + (5 -> 6 -> 4) 7 -> 0 -> 8 ListNode* l1 = new ListNode(2); l1->next = new ListNode(4); l1->next->next = new ListNode(3); ListNode* l2 = new ListNode(5); l2->next = new ListNode(6); l2->next->next = new ListNode(4); ListNode* result = addTwoNumbers(l1,l2); // NULL + (2 -> 4 -> 3) result = addTwoNumbers(NULL,l1); // (2 -> 4 -> 3) + (5 -> 6 -> 4 -> 4) l2->next->next->next = new ListNode(4); result = addTwoNumbers(l1,l2); // 1 + 9->9 l1 = new ListNode(1); l2 = new ListNode(9); l2->next = new ListNode(9); result = addTwoNumbers(l1,l2); }
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原文地址:http://www.cnblogs.com/Quincy/p/5213028.html