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def reduceNum(n): ‘‘‘题目:将一个正整数分解质因数。例如:输入90,打印出90=2*3*3*5‘‘‘ print ‘{} = ‘.format(n), if not isinstance(n, int) or n <= 0 : print ‘Please input a valid number !‘ exit(0) elif n in [1] : print ‘{}‘.format(n) while n not in [1] : # 循环保证递归 for index in xrange(2, n + 1) : if n % index == 0: n /= index # let n equal to it n/index if n == 1: # This is the point print index # The last one else : # index 一定是素数 print ‘{} *‘.format(index), break reduceNum(1250895) reduceNum(23)
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原文地址:http://www.cnblogs.com/peiqianggao/p/5237470.html