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Given an integer array, heapify it into a min-heap array.
Given [3,2,1,4,5], return [1,2,3,4,5] or any legal heap array.
public class Solution { /** * @param A: Given an integer array * @return: void */ public void heapify(int[] A) { // write your code here if(A == null || A.length == 0) return; for(int i = A.length / 2; i >= 0; i--){ adjust(A, i); } return; } public void adjust(int[] A, int i){ int left = i * 2 + 1; int right = i * 2 + 2; int min = i; if(left < A.length && A[left] < A[min]) min = left; if(right < A.length && A[right] < A[min]) min = right; if(i == min) return; swap(A, i, min); adjust(A, min); return; } public void swap(int[] A, int i, int j){ int temp = A[i]; A[i] = A[j]; A[j] = temp; return; } }
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原文地址:http://www.cnblogs.com/goblinengineer/p/5305993.html