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SQL简单语句总结习题

时间:2016-03-28 10:33:02      阅读:247      评论:0      收藏:0      [点我收藏+]

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创建一个表记员工个人信息:

 

              --创建一个表
create table  plspl_company_info(
              empno number(5) not null, 
              ename varchar2(10) not null,
              job varchar2(10),
              manager number(5),
              hiredate date,
              sal  number(5),
              comm  number(5),
              deptno number(3)
              );
            
insert into plspl_company_info values (7369, SMITH, CLERK, 7902, date 1980-12-17, 800, NULL, 10);
insert into plspl_company_info values (7293, ALLEN, SALESMAN, 7689, date 1981-03-27, 1867, NULL, 20);
insert into plspl_company_info values (7562, JAMES, SALESMAN, 7689, date 1981-09-11, 1796, NULL, 20);
insert into plspl_company_info values (7936, JONES, ANAYST, 7656, date 1980-09-01, 3250, NULL, 30);
insert into plspl_company_info values (7688, WEST, MANAGER, 7839, date 1981-02-28, 2985, 900, 40);
insert into plspl_company_info values (7499, PAUL, MANAGER, 7839, date 1980-03-26, 3600, NULL, 40);
insert into plspl_company_info values (7778, FORD, CLERK, 7902, date 1987-04-17, 960, NULL, 10);
insert into plspl_company_info values (7289, ADAMS, SALESMAN, 7689, date 1980-01-09, 1956, NULL, 20);
insert into plspl_company_info values (7531, MATIN, SALESMAN, 7689, date 1980-05-14, 1906, NULL, 20);
insert into plspl_company_info values (7916, KING, ANAYST, 7656, date 1982-06-04, 2864, NULL, 30);
insert into plspl_company_info values (7365, BLKAE, CLERK, 7902, date 1981-09-11, 1200, 1100, 10);
insert into plspl_company_info values (7784, CHRIS, CLERK, 7902, date 1981-07-16, 1376, NULL, 10);

select * from plspl_company_info;


执行结果:

SQL>

Table created

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

1 row inserted

EMPNO ENAME JOB MANAGER HIREDATE SAL COMM DEPTNO
------ ---------- ---------- ------- ----------- ------ ------ ------
7369 SMITH CLERK 7902 1980/12/17 800 10
7293 ALLEN SALESMAN 7689 1981/3/27 1867 20
7562 JAMES SALESMAN 7689 1981/9/11 1796 20
7936 JONES ANAYST 7656 1980/9/1 3250 30
7688 WEST MANAGER 7839 1981/2/28 2985 900 40
7499 PAUL MANAGER 7839 1980/3/26 3600 40
7778 FORD CLERK 7902 1987/4/17 960 10
7289 ADAMS SALESMAN 7689 1980/1/9 1956 20
7531 MATIN SALESMAN 7689 1980/5/14 1906 20
7916 KING ANAYST 7656 1982/6/4 2864 30
7365 BLKAE CLERK 7902 1981/9/11 1200 1100 10
7784 CHRIS CLERK 7902 1981/7/16 1376 10


12 rows selected

SQL>

 

习题:

1,选出部门30里的所有员工信息

select * from plspl_company_info where deptno = 30;

 2,列出所有办事员(CLERK)的姓名,编号和部门编号

select ename, empno , deptno from  plspl_company_info where job = CLERK;

3,找出薪金高于佣金60%的员工

select * from plspl_company_info where comm > sal*0.6 ;

4,找出部门10的所有经理(MANAGER)和部门20的所有办事员(CLERK)

select * from plspl_company_info where (deptno = 10 and job = MANAGER) or (deptno = 20 and job = CLERK) ;

5,找出部门10的所有经理(MANAGER)和部门20的所有办事员(CLERK),以及既不是经理有不是办事员,但薪金大于或等于2000的所有员工的详细资料

select * 
from plspl_company_info 
where (deptno = 10 and job = MANAGER) or (deptno = 20 and job = CLERK) or ((job not in(MANAGER, CLERK)) and sal >= 2000) ;

6,找出收取佣金的员工的不同工作

select distinct job from plspl_company_info where comm is not null ;

7,找出不收取佣金或者收取佣金低于100的原

select * from plspl_company_info where (comm is  null) or comm < 100 ;

8,显示不带“R”的员工姓名

select * from plspl_company_info where ename not like %A%;

9,显示姓名字段的任何位置包含‘A‘的所有员工的姓名,显示结果按照基本工资由高到低;如果工资相同,则按照雇佣年限由早到晚排序;如果雇佣时间相同,则按照职位排序

select * from plspl_company_info where ename like %A% order by sal DESC, hiredate, job;

 

SQL简单语句总结习题

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原文地址:http://www.cnblogs.com/xiaoxing/p/5327994.html

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