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本程序的基本功能是:输入数组的行数和列数,程序自动生成对应规格的数组,在满足连通性的情况下,求最大的子数组的和。
主要的功能的实现是依靠图的遍历。
团队成员:王硕 http://home.cnblogs.com/u/WS1004/
#include<fstream> #include<iostream> #include<ctime> using namespace std; #define RAND16 ((rand()<<1) + (rand()&1)) #define N 100 # define WIDE 4294967296 typedef struct { long long int dian[N]; long long int xian[N][N]; long long int dianx, xianx; }A; void set(A &shu, int x, int y) { shu.dianx = x*y; srand((_int32)time(NULL)); for (int i = 1; i <= shu.dianx; i++) { shu.dian[i] = (RAND16 << 16) + RAND16; if (rand() % 2 == 1) shu.dian[i] = shu.dian[i] * (-1); } for (int i = 1; i <= shu.dianx; i += y) { for (int j = i; j <= i + y - 2; j++) { shu.xian[j][j + 1] = 1; shu.xian[j + 1][j] = 1; } } for (int i = 1 + y; i<shu.dianx; i += y) { for (int j = i; j <= i + x - 1; j++) { shu.xian[j][j - y] = 1; shu.xian[j - y][j] = 1; } } } void bianli(A &shu, long long int v, long long int visit[], long long int &b, long long int &max, long long int x) { visit[v] = 1; max += shu.dian[v]; if (max >= b) b = max; int a = 0, bo = 0; for (int w = 1; w <= shu.dianx; w++) { for (int c = 1; c <= shu.dianx; c++) { if ((visit[w] == 0) && (shu.xian[c][w] == 1) && (visit[c] == 1)) { a = w; bo = 1; break; } } if (bo == 1) break; } for (int w = 1; w <= shu.dianx; w++) { for (int c = 1; c <= shu.dianx; c++) { if ((visit[w] == 0) && (shu.xian[c][w] == 1) && (visit[c] == 1)) { if (shu.dian[a]<shu.dian[w]) a = w; } } } if (b + shu.dian[a]<0) { shu.xian[v][a] = 0; } else bianli(shu, a, visit, b, max, x); } int NoVisit(long long int visit[], A shu) { int k = 0, i; for (i = 1; i <= shu.dianx; i++) { if (visit[i] == 0) { k = i; break; } } return k; } int main() { cout << "请输入数组行列数:" << endl; int x, y; cin >> x >> y; A shu; set(shu, x, y); ofstream fout("D:\\input.txt",ios::binary); for (int i = 1; i <= shu.dianx; i++) { fout << shu.dian[i] ; if (shu.xian[i][i + 1] == 1) fout << " "; else fout << "\r\n"; } long long int v = 1, b[N] = { 0 }, h = 0; for (int i = 1; i <= shu.dianx; i++) { if (shu.dian[i]<0) { b[i] = shu.dian[i]; } else { long long int visit[N] = { 0 }; long long int max = 0; bianli(shu, i, visit, b[i], max, x); } } long long int max = b[1]; for (int i = 2; i <= shu.dianx; i++) { if (b[i]>max) max = b[i]; } fout << "最大联通子数组的和为:" << max << endl; }
总结:
本次编程中出现了一些问题,在文件中输出不能换行,后上网得知把endl改为\r\n即可。
此次编程有上两次编程的基础,化难为易的思想发挥了非常大的作用。
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原文地址:http://www.cnblogs.com/liyan-luckygirl/p/5352899.html