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C++ ssd5 25 optional exercise 6

时间:2016-04-06 23:08:27      阅读:159      评论:0      收藏:0      [点我收藏+]

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// parts.h

#ifndef _PARTS_H_
#define _PARTS_H_

#include <vector>
#include <map>
#include <string>
#include <iostream>

using namespace std;

//**************** Part ****************
class Part {

private:

static int count;

public:
string name;
map<string, int> subparts;

// TODO: Finish declaration

Part(string const &n) : name(n),subparts(){};
void describe(void);
int count_howmany(Part const *p);
};


//**************** NameContainer ****************
class NameContainer {

private:
map<string, Part*> name_map;


public:

NameContainer(void) {};

Part* lookup(string const &name) {

// TODO: Finish implementation
Part *pt = new Part(name);
name_map.insert(pair<string, Part*>(name,pt));//如果存在则第二次会插入失败,确保不会产生两个相同的PArt对象
map<string, Part*>::iterator iter;
iter = name_map.find(name);
return iter->second;
}


};

NameContainer partContainer;

//**************** Part Member Functions ****************
void Part::describe(void) {

// TODO: Finish implementation
cout << "part " << this->name << " subparts are :" << endl;
map<string, int>::iterator iter;
for (iter = subparts.begin(); iter != subparts.end(); iter++)//iterator to traverse
{
cout << iter->first << " " << iter->second << endl;
}

}

int Part::count = 1;

int Part::count_howmany(Part const *p) {

// TODO: Finish implementation

if (this->name == p->name)
return 1;
else
{
int total = 0;
map<string, int>::iterator iter;
for (iter = subparts.begin(); iter != subparts.end(); iter++)//遍历,此处是按字母升序完成
{
Part * pt = partContainer.lookup(iter->first);
total += pt->count_howmany(p)*iter->second;//注意+=号而不是等号,如果是等号则是替换;

}
return total;
}
/*int num;
if (p->name == this->name)
return 0;
else
{

map<string, int>::iterator iter;

for (iter = subparts.begin(); iter != subparts.end(); iter++)
{

Part * pt = partContainer.lookup(iter->first);
if (pt->subparts.empty() && iter->first != p->name)
continue;

count = count*(iter->second);
pt->count_howmany(p);
}
num = count;



}

return num;
*/
}

//**************** Miscellaneous Functions ****************
void add_part(string const &x, int q, string const &y) {

// TODO: Finish implementation
Part* xp = partContainer.lookup(x);
xp->subparts.insert(pair<string, int>(y,q));

}

#endif
#pragma once

C++ ssd5 25 optional exercise 6

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原文地址:http://www.cnblogs.com/bigminnow/p/5361370.html

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