最小（大）堆找出数组的最小（大）的k项值

//最小堆实现
void MyGlobal::min_heapify(int *a, int* b,int left, int right)
{
    int child = 0;
    int tmp = 0;
    int tempb = 0;
    int parent = left;
    assert(a != NULL);
    for (tmp = a[parent],tempb=b[parent]; LEFTSON(parent) <= right; parent = child)
    {
        child = LEFTSON(parent);
        if (child != parent && a[child] > a[child + 1])
        {
            child++;
        }
        if (a[child] < tmp)
        {
            a[parent] = a[child];
            b[parent] = b[child];
        }
        else   //满足最小堆的特性，直接退出
            break;
    }
        a[parent] = tmp;
        b[parent] = tempb;
}
//创建最小堆
void MyGlobal::build_minheap(int *a,int*b, int size)
{
    int i = PARENT(size);
    assert(a != NULL);
    for (; i >= 0; --i)
    {
        min_heapify(a,b, i, size - 1);
    }
}
//主函数
int* MyGlobal::find_Kmin_num_4(int *a, int* b, int size, int k)
{
    int i = 0;
    assert(a != NULL);
    build_minheap(a, b, size - 1);
    int* m = new int[k];
    for ( i = 0; i < k; ++i)
    {
        printf("%d\t", b[0]);
        //删除a[0],释放a[size-1-i]
        m[i] = b[0];
        a[0] = a[size - 1 - i];
        min_heapify(a,b ,0, size - 2 - i);        
    }
    printf("\n");
    return m;
}