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Spring Resource

时间:2016-04-16 16:38:54      阅读:208      评论:0      收藏:0      [点我收藏+]

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1:资源访问

  在Sun所提供的标准API里,资源访问通常由Java.net.URL和文件IO来完成,如果需要访问来自网络的资源时,则通常会选择URL类。

  Url类可以处理一些常规的资源访问问题,但是依然不能很好地满足所有底层资源访问的需要,比如,暂时还无法在类加载路径或相对于ServletContext的路径中访问资源,也无法检查所指向的资源是否存在。

  Spring对其内部使用到的资源实现了自己的抽象结构:Resource接口来封装底层资源。

  InputStreamSource封装任何能返回InputStream的类,比如File,Classpath下的资源和Byte Array等。它只有一个方法定义:getInputStream(),该方法返回一个新的InputStream对象。

  Resource接口本身没有提供访问任何底层资源的实现逻辑,针对不同的底层资源,Spring将会提供不同的Resource实现类,不同的实现类负责不同的资源访问逻辑。

  Spring的Resource设计是一种典型的策略模式,通过使用Resource接口,客户端程序可以在不同的资源访问策略之间自由切换。

package org.springframework.core.io;

import java.io.IOException;
import java.io.InputStream;

public interface InputStreamSource {

    InputStream getInputStream() throws IOException;

}
package org.springframework.core.io;

import java.io.File;
import java.io.IOException;
import java.net.URI;
import java.net.URL;

public interface Resource extends InputStreamSource {

  //存在性
boolean exists();   
  //可读性
boolean isReadable();
  //是否处于打开状态
boolean isOpen(); URL getURL() throws IOException; URI getURI() throws IOException; File getFile() throws IOException; long contentLength() throws IOException; long lastModified() throws IOException;
  //基于当前资源创建相对资源 Resource createRelative(String relativePath)
throws IOException;
  //不带路径信息的文件名 String getFilename();
  //用于在错误处理中打印信息 String getDescription(); }

2:Resource实现类

  UrlResource:访问网络资源的实现类

  ClassPathResource:访问类加载路径里资源的实现类

  FileSystemResource:访问文件系统里资源的实现类

  ServletContextResource:访问相对于ServletContext路径下的资源的实现类

  InputStreamResource:访问输入流资源的实现类

  ByteArrayResouce:访问字节数组资源的实现类

  1)UrlResource

  file:用于访问文件系统,  http:用于通过HTTP协议访问资源,  ftp:用于通过FTP协议访问资源

package org.springframework.core.io;

import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URI;
import java.net.URISyntaxException;
import java.net.URL;
import java.net.URLConnection;

import org.springframework.util.Assert;
import org.springframework.util.ResourceUtils;
import org.springframework.util.StringUtils;

public class UrlResource extends AbstractFileResolvingResource {

    private final URI uri;

    private final URL url;

    private final URL cleanedUrl;

    public UrlResource(URI uri) throws MalformedURLException {
        Assert.notNull(uri, "URI must not be null");
        this.uri = uri;
        this.url = uri.toURL();
        this.cleanedUrl = getCleanedUrl(this.url, uri.toString());
    }

    public UrlResource(URL url) {
        Assert.notNull(url, "URL must not be null");
        this.url = url;
        this.cleanedUrl = getCleanedUrl(this.url, url.toString());
        this.uri = null;
    }

    public UrlResource(String path) throws MalformedURLException {
        Assert.notNull(path, "Path must not be null");
        this.uri = null;
        this.url = new URL(path);
        this.cleanedUrl = getCleanedUrl(this.url, path);
    }

    public UrlResource(String protocol, String location) throws MalformedURLException  {
        this(protocol, location, null);
    }

    
    public UrlResource(String protocol, String location, String fragment) throws MalformedURLException  {
        try {
            this.uri = new URI(protocol, location, fragment);
            this.url = this.uri.toURL();
            this.cleanedUrl = getCleanedUrl(this.url, this.uri.toString());
        }
        catch (URISyntaxException ex) {
            MalformedURLException exToThrow = new MalformedURLException(ex.getMessage());
            exToThrow.initCause(ex);
            throw exToThrow;
        }
    }

    private URL getCleanedUrl(URL originalUrl, String originalPath) {
        try {
            return new URL(StringUtils.cleanPath(originalPath));
        }
        catch (MalformedURLException ex) {
            // Cleaned URL path cannot be converted to URL
            // -> take original URL.
            return originalUrl;
        }
    }

    @Override
    public InputStream getInputStream() throws IOException {
        URLConnection con = this.url.openConnection();
        ResourceUtils.useCachesIfNecessary(con);
        try {
            return con.getInputStream();
        }
        catch (IOException ex) {
            // Close the HTTP connection (if applicable).
            if (con instanceof HttpURLConnection) {
                ((HttpURLConnection) con).disconnect();
            }
            throw ex;
        }
    }

    
    @Override
    public URL getURL() throws IOException {
        return this.url;
    }

    
    @Override
    public URI getURI() throws IOException {
        if (this.uri != null) {
            return this.uri;
        }
        else {
            return super.getURI();
        }
    }

    @Override
    public File getFile() throws IOException {
        if (this.uri != null) {
            return super.getFile(this.uri);
        }
        else {
            return super.getFile();
        }
    }

    @Override
    public Resource createRelative(String relativePath) throws MalformedURLException {
        if (relativePath.startsWith("/")) {
            relativePath = relativePath.substring(1);
        }
        return new UrlResource(new URL(this.url, relativePath));
    }


    @Override
    public String getFilename() {
        return new File(this.url.getFile()).getName();
    }

    @Override
    public String getDescription() {
        return "URL [" + this.url + "]";
    }

    @Override
    public boolean equals(Object obj) {
        return (obj == this ||
            (obj instanceof UrlResource && this.cleanedUrl.equals(((UrlResource) obj).cleanedUrl)));
    }

    @Override
    public int hashCode() {
        return this.cleanedUrl.hashCode();
    }

}

  2)ClassPathResource

        public ClassPathResource(String path) {
        this(path, (ClassLoader) null);
    }

    public ClassPathResource(String path, ClassLoader classLoader) {
        Assert.notNull(path, "Path must not be null");
        String pathToUse = StringUtils.cleanPath(path);
        if (pathToUse.startsWith("/")) {
            pathToUse = pathToUse.substring(1);
        }
        this.path = pathToUse;
        this.classLoader = (classLoader != null ? classLoader : ClassUtils.getDefaultClassLoader());
    }
     
    public final ClassLoader getClassLoader() {
        return (this.clazz != null ? this.clazz.getClassLoader() : this.classLoader);
    }

    @Override
    public InputStream getInputStream() throws IOException {
        InputStream is;
        if (this.clazz != null) {
            is = this.clazz.getResourceAsStream(this.path);
        }
        else if (this.classLoader != null) {
            is = this.classLoader.getResourceAsStream(this.path);
        }
        else {
            is = ClassLoader.getSystemResourceAsStream(this.path);
        }
        if (is == null) {
            throw new FileNotFoundException(getDescription() + " cannot be opened because it does not exist");
        }
        return is;
    }

  3)FileSystemResource

    public FileSystemResource(String path) {
        Assert.notNull(path, "Path must not be null");
        this.file = new File(path);
        this.path = StringUtils.cleanPath(path);
    }

    @Override
    public InputStream getInputStream() throws IOException {
        return new FileInputStream(this.file);
    }

  4)ByteArrayResource

    public ByteArrayResource(byte[] byteArray) {
        this(byteArray, "resource loaded from byte array");
    }


    @Override
    public InputStream getInputStream() throws IOException {
        return new ByteArrayInputStream(this.byteArray);
    }

分析:

  通过Resource,我们需要获取输入流InupStream,FileSystemResource和ByteArrayResource的getInputStream()方法更好理解。

  以UrlResource举例:

通常会传进来一个String,比如说file:D://zhao.txt    

public UrlResource(String path) throws MalformedURLException {
  Assert.notNull(path, "Path must not be null");
  this.uri = null;
  this.url = new URL(path);
  this.cleanedUrl = getCleanedUrl(this.url, path);
}

我们需要用到getCleanUrl(this.url,path)

private URL getCleanedUrl(URL originalUrl, String originalPath) {
  try {
    return new URL(StringUtils.cleanPath(originalPath));
  }
  catch (MalformedURLException ex) {
    return originalUrl;
  }
}

我们的目的是把传入的String拆开,得到 : 前的内容,告诉我们用什么协议,得到 : 后的内容,告诉我们位置在哪

    public static String cleanPath(String path) {
        if (path == null) {
            return null;
        }
        String pathToUse = replace(path, WINDOWS_FOLDER_SEPARATOR, FOLDER_SEPARATOR);

        // Strip prefix from path to analyze, to not treat it as part of the
        // first path element. This is necessary to correctly parse paths like
        // "file:core/../core/io/Resource.class", where the ".." should just
        // strip the first "core" directory while keeping the "file:" prefix.
        int prefixIndex = pathToUse.indexOf(":");
        String prefix = "";
        if (prefixIndex != -1) {
            prefix = pathToUse.substring(0, prefixIndex + 1);
            if (prefix.contains("/")) {
                prefix = "";
            }
            else {
                pathToUse = pathToUse.substring(prefixIndex + 1);
            }
        }
        if (pathToUse.startsWith(FOLDER_SEPARATOR)) {
            prefix = prefix + FOLDER_SEPARATOR;
            pathToUse = pathToUse.substring(1);
        }

        String[] pathArray = delimitedListToStringArray(pathToUse, FOLDER_SEPARATOR);
        List<String> pathElements = new LinkedList<String>();
        int tops = 0;

        for (int i = pathArray.length - 1; i >= 0; i--) {
            String element = pathArray[i];
            if (CURRENT_PATH.equals(element)) {
                // Points to current directory - drop it.
            }
            else if (TOP_PATH.equals(element)) {
                // Registering top path found.
                tops++;
            }
            else {
                if (tops > 0) {
                    // Merging path element with element corresponding to top path.
                    tops--;
                }
                else {
                    // Normal path element found.
                    pathElements.add(0, element);
                }
            }
        }

        // Remaining top paths need to be retained.
        for (int i = 0; i < tops; i++) {
            pathElements.add(0, TOP_PATH);
        }

        return prefix + collectionToDelimitedString(pathElements, FOLDER_SEPARATOR);
    }

 

Spring Resource

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原文地址:http://www.cnblogs.com/zhao307/p/5398459.html

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