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def fe(L,n):
sb = len(L)
if n > sb:
return L
for i in range(sb):
print i
if L[i] >= L[n]:
a =L[i]
L[i] = L[n]
L[n] = a
print L
fe(L,n+1)
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原文地址：http://www.cnblogs.com/nerdlerss/p/5463979.html
