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Use Integer.parseInt(String input, int radix)
to convert from any type of number to an Integer
.
String binaryNumber = "10101"; int decimal1 = Integer.parseInt(binaryNumber, 2); System.out.println(binaryNumber + " in Base 10 : " + decimal1); String octalNumber = "456"; int decimal2 = Integer.parseInt(octalNumber, 8); System.out.println(octalNumber + " in Base 10 : " + decimal2); String hexNumber = "ABCD"; int decimal3 = Integer.parseInt(hexNumber, 16); System.out.println(hexNumber + " in Base 10 : " + decimal3); Output: 10101 in Base 10 : 21 456 in Base 10 : 302 ABCD in Base 10 : 43981
Use Integer.toString(int input, int radix)
to convert from an Integer
to any type of base number.
Integer decimal1 = 21; String binaryNumber = Integer.toString(decimal1, 2); System.out.println(decimal1 + " in Base 2 : " + binaryNumber); Integer decimal2 = 302; String octalNumber = Integer.toString(decimal2, 8); System.out.println(decimal2 + " in Base 8 : " + octalNumber); Integer decimal3 = 43981; String hexNumber = Integer.toString(decimal3, 16); System.out.println(decimal2 + " in Base 16 : " + hexNumber); Output: 21 in Base 2 : 10101 302 in Base 8 : 456 43981 in Base 16 : abcd
Integer
class does provide lots of unitily methods to be consumed directly. Check out them in java doc.
Integer decimal1 = 21; System.out.println(decimal1 + " in Base 2 : " + Integer.toBinaryString(decimal1)); Integer decimal2 = 302; System.out.println(decimal2 + " in Base 8 : " + Integer.toOctalString(decimal2)); Integer decimal3 = 43981; System.out.println(decimal3 + " in Base 16 : " + Integer.toHexString(decimal3)); Output: 21 in Base 2 : 10101 302 in Base 8 : 456 43981 in Base 16 : abcd
Binary, Octal, and Hexadecimal Conversions in Java
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原文地址:http://www.cnblogs.com/skyball/p/5467470.html