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python基本数据类型之集合set

时间:2016-05-07 23:51:16      阅读:354      评论:0      收藏:0      [点我收藏+]

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一、集合的定义

set集合,是一个无序且不重复的元素集合。

集合对象是一组无序排列的可哈希的值,集合成员可以做字典中的键。集合支持用in和not in操作符检查成员,由len()内建函数得到集合的基数(大小), 用 for 循环迭代集合的成员。但是因为集合本身是无序的,不可以为集合创建索引或执行切片(slice)操作,也没有键(keys)可用来获取集合中元素的值。

二、集合的创建

s = set()
s = {11,22,33,44}

*注:创建空集合时,只能用set(),如果用第二种方法s={},创建的实际上是一个空字典。
s = {}
print(type(s))
<class dict>
a=set(boy)
b=set([y, b, o,o])
c=set({"k1":v1,k2:v2})
d={k1,k2,k2}
e={(k1, k2,k2)}
print(a,type(a))
print(b,type(b))
print(c,type(c))
print(d,type(d))
print(e,type(e))
执行结果如下:
{o, b, y} <class set>
{o, b, y} <class set>
{k1, k2} <class set>
{k1, k2} <class set>
{(k1, k2, k2)} <class set>

三、集合的功能

技术分享
class set(object):
    """
    set() -> new empty set object
    set(iterable) -> new set object
     
    Build an unordered collection of unique elements.
    """
    def add(self, *args, **kwargs): # real signature unknown
        """
        Add an element to a set,添加元素
         
        This has no effect if the element is already present.
        """
        pass
 
    def clear(self, *args, **kwargs): # real signature unknown
        """ Remove all elements from this set. 清楚内容"""
        pass
 
    def copy(self, *args, **kwargs): # real signature unknown
        """ Return a shallow copy of a set. 浅拷贝  """
        pass
 
    def difference(self, *args, **kwargs): # real signature unknown
        """
        Return the difference of two or more sets as a new set. A中存在,B中不存在
         
        (i.e. all elements that are in this set but not the others.)
        """
        pass
 
    def difference_update(self, *args, **kwargs): # real signature unknown
        """ Remove all elements of another set from this set.  从当前集合中删除和B中相同的元素"""
        pass
 
    def discard(self, *args, **kwargs): # real signature unknown
        """
        Remove an element from a set if it is a member.
         
        If the element is not a member, do nothing. 移除指定元素,不存在不保错
        """
        pass
 
    def intersection(self, *args, **kwargs): # real signature unknown
        """
        Return the intersection of two sets as a new set. 交集
         
        (i.e. all elements that are in both sets.)
        """
        pass
 
    def intersection_update(self, *args, **kwargs): # real signature unknown
        """ Update a set with the intersection of itself and another.  取交集并更更新到A中 """
        pass
 
    def isdisjoint(self, *args, **kwargs): # real signature unknown
        """ Return True if two sets have a null intersection.  如果没有交集,返回True,否则返回False"""
        pass
 
    def issubset(self, *args, **kwargs): # real signature unknown
        """ Report whether another set contains this set.  是否是子序列"""
        pass
 
    def issuperset(self, *args, **kwargs): # real signature unknown
        """ Report whether this set contains another set. 是否是父序列"""
        pass
 
    def pop(self, *args, **kwargs): # real signature unknown
        """
        Remove and return an arbitrary set element.
        Raises KeyError if the set is empty. 移除元素
        """
        pass
 
    def remove(self, *args, **kwargs): # real signature unknown
        """
        Remove an element from a set; it must be a member.
         
        If the element is not a member, raise a KeyError. 移除指定元素,不存在保错
        """
        pass
 
    def symmetric_difference(self, *args, **kwargs): # real signature unknown
        """
        Return the symmetric difference of two sets as a new set.  对称交集
         
        (i.e. all elements that are in exactly one of the sets.)
        """
        pass
 
    def symmetric_difference_update(self, *args, **kwargs): # real signature unknown
        """ Update a set with the symmetric difference of itself and another. 对称交集,并更新到a中 """
        pass
 
    def union(self, *args, **kwargs): # real signature unknown
        """
        Return the union of sets as a new set.  并集
         
        (i.e. all elements that are in either set.)
        """
        pass
 
    def update(self, *args, **kwargs): # real signature unknown
        """ Update a set with the union of itself and others. 更新 """
        pass
源码

基本功能:

  • 增加
a=set(python)
a.add(tina)
print(a)
b=set(python)
b.update(tina)
print(b)
执行结果如下:
{tina, o, p, n, t, y, h}
{o, i, p, a, n, t, y, h}
##################
由以上代码可以看出,add是单个元素的添加,而update是批量的添加。输出结果是无序的,并非添加到尾部。
  • 删除(remove,discard,pop)
c={p, i, h, n, o, y, t}
c.remove(p)
print(c)
c={‘p‘, ‘i‘, ‘h‘, ‘n‘, ‘o‘, ‘y‘, ‘t‘}
c.discard(‘p‘)
print(c)
c={‘p‘, ‘i‘, ‘h‘, ‘n‘, ‘o‘, ‘y‘, ‘t‘}
c.pop()
print(c)
执行结果如下: {i, h, t, o, y, n} 
#####
当执行c.remove(p,i)和c.discard(‘p‘,‘i‘)时,报错:TypeError: remove() takes exactly one argument (2 given),说明remove和discard删除元素时都只能一个一个的删,同add对应。
#################################################################################
remove,pop和discard的区别:
discard删除指定元素,当指定元素不存在时,不报错;
remove
删除指定元素,但当指定元素不存在时,报错:KeyError。
pop删除任意元素,并可将移除的元素赋值给一个变量,不能指定元素移除。
  • 清空
c={p, i, h, n, o, y, t}
c.clear()
print(c)
执行结果如下:
set()

set的特有功能:

s1 = {0}
s2 = {i % 2 for i in range(10)}
s = set(hi)
t = set([h, e, l, l, o])
print(s.intersection(t), s & t)  # 交集
print(s.union(t), s | t)   # 并集
print(s.difference(t), s - t)  # 差集
print(s.symmetric_difference(t), s ^ t) # 对称差集
print(s1.issubset(s2), s1 <= s2) # 子集(被包含)
print(s1.issuperset(s2), s1 >= s2)   # 父集(包含)

执行结果如下:
{h} {h}
{i, e, h, l, o} {i, e, h, l, o}
{i} {i}
{e, l, o, i} {e, l, o, i}
True True
False False
s = {11,22,33}
t = {22,44}
print(s.isdisjoint(t))#(disjoint脱节的,)即如果没有交集,返回True,否则返回False
s.difference_update(t)#将差集覆盖到源集合,即从当前集合中删除和B中相同的元素
print(s)
执行结果如下:
False
{33, 11}

s = {11,22,33}
t = {22,44}
s.intersection_update(t)#将交集覆盖到源集合
print(s)
执行结果如下:
{22}

s = {11,22,33}
t = {22,44}
s.symmetric_difference_update(t)#将对称差集覆盖到源集合
print(s)
执行结果如下:
{33, 11, 44}

四、集合的转换

se = set(range(4))
li = list(se)
tu = tuple(se)
st = str(se)
print(li,type(li))
print(tu,type(tu))
print(st,type(st))
执行结果如下:
[0, 1, 2, 3] <class list>
(0, 1, 2, 3) <class tuple>
{0, 1, 2, 3} <class str>

 五、练习题

 寻找差异:哪些需要删除?哪些需要新建?哪些需要更新?

# 数据库中原有
old_dict = {
    "#1":{ hostname:c1, cpu_count: 2, mem_capicity: 80 },
    "#2":{ hostname:c1, cpu_count: 2, mem_capicity: 80 }
    "#3":{ hostname:c1, cpu_count: 2, mem_capicity: 80 }
}
   
# cmdb 新汇报的数据
new_dict = {
    "#1":{ hostname:c1, cpu_count: 2, mem_capicity: 800 },
    "#3":{ hostname:c1, cpu_count: 2, mem_capicity: 80 }
    "#4":{ hostname:c2, cpu_count: 2, mem_capicity: 80 }
} 

注意:无需考虑内部元素是否改变,只要原来存在,新汇报也存在,就是需要更新

del_dict = set(old_dict).difference(set(new_dict))
add_dict = set(new_dict).difference(set(old_dict))
update_dict = set(new_dict).intersection(set(old_dict))
print(del_dict)
print(add_dict)
print(update_dict)
执行结果如下:
{#2}
{#4}
{#3, #1}

 

python基本数据类型之集合set

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原文地址:http://www.cnblogs.com/tina-python/p/5468495.html

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