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题目来源:
https://leetcode.com/problems/min-stack/
题意分析:
实现一个小的栈,包括初始化,push,pop,top,和getMin。
题目思路:
私用是用两个数组来处理。
代码(python):
1 class MinStack(object): 2 def __init__(self): 3 """ 4 initialize your data structure here. 5 """ 6 self.stack1 = [] 7 self.stack2 = [] 8 9 10 def push(self, x): 11 """ 12 :type x: int 13 :rtype: nothing 14 """ 15 self.stack1.append(x) 16 if len(self.stack2) == 0 or x <= self.stack2[-1]: 17 self.stack2.append(x) 18 19 20 def pop(self): 21 """ 22 :rtype: nothing 23 """ 24 tmp = self.stack1.pop() 25 if tmp == self.stack2[-1]: 26 self.stack2.pop() 27 28 29 def top(self): 30 """ 31 :rtype: int 32 """ 33 return self.stack1[-1] 34 35 def getMin(self): 36 """ 37 :rtype: int 38 """ 39 return self.stack2[-1] 40
[LeetCode]题解(python):155-Min Stack
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原文地址:http://www.cnblogs.com/chruny/p/5478505.html