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C#将图片2值化示例代码，原图及二值化后的图片如下：
原图：
二值化后的图像：
实现代码：
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using System;using System.Drawing;namespace BMP2Grey{ class Program { static void ToGrey(Bitmap img1) { for (int i = 0; i < img1.Width; i++) { for (int j = 0; j < img1.Height; j++) { Color pixelColor = img1.GetPixel(i, j); //计算灰度值 int grey = (int)(0.299 * pixelColor.R + 0.587 * pixelColor.G + 0.114 * pixelColor.B); Color newColor = Color.FromArgb(grey, grey, grey); img1.SetPixel(i, j, newColor); } } } static void Thresholding(Bitmap img1) { int[] histogram = new int[256]; int minGrayValue=255, maxGrayValue=0; //求取直方图 for (int i = 0; i < img1.Width; i++) { for (int j = 0; j < img1.Height; j++) { Color pixelColor = img1.GetPixel(i, j); histogram[pixelColor.R]++; if (pixelColor.R > maxGrayValue) maxGrayValue = pixelColor.R; if (pixelColor.R < minGrayValue) minGrayValue = pixelColor.R; } } //迭代计算阀值 int threshold = -1; int newThreshold = (minGrayValue + maxGrayValue) / 2; for(int iterationTimes = 0; threshold != newThreshold && iterationTimes < 100; iterationTimes++) { threshold = newThreshold; int lP1 =0; int lP2 =0; int lS1 = 0; int lS2 = 0; //求两个区域的灰度的平均值 for (int i = minGrayValue;i < threshold;i++) { lP1 += histogram[i] * i; lS1 += histogram[i]; } int mean1GrayValue = (lP1 / lS1); for (int i = threshold+1;i < maxGrayValue;i++) { lP2 += histogram[i] * i; lS2 += histogram[i]; } int mean2GrayValue = (lP2 / lS2); newThreshold = (mean1GrayValue + mean2GrayValue) / 2; } //计算二值化 for (int i = 0; i < img1.Width; i++) { for (int j = 0; j < img1.Height; j++) { Color pixelColor = img1.GetPixel(i, j); if (pixelColor.R > threshold) img1.SetPixel(i, j, Color.FromArgb(255, 255, 255)); else img1.SetPixel(i, j, Color.FromArgb(0, 0, 0)); } } } static void Main(string[] args) { try { //打开位图文件 Bitmap img1 = new Bitmap("test.jpg", true); //灰度化 ToGrey(img1); //二值化 Thresholding(img1); //写回位图文件 img1.Save("output.jpg"); Console.WriteLine("Converted."); } catch (ArgumentException) { Console.WriteLine("Invalid usage!"); Console.WriteLine("Usage: bmp2grey source object"); } } }} |
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原文地址：http://www.cnblogs.com/waw/p/5484148.html
