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C++标准库通过template numeric_limits提供数值类型的极限值。使用这个模板,可以一定程度的提高程序的可移植性。
#include <iostream> #include <limits> using std::cout; using std::endl; using std::numeric_limits; int main(){ cout<<" the min of char is: "<<(int)numeric_limits<char>::min()<<endl; cout<<" the max of char is: "<<(int)numeric_limits<char>::max()<<endl; cout<<" the min of short is: "<<numeric_limits<short>::min()<<endl; cout<<" the max of short is: "<<numeric_limits<short>::max()<<endl; cout<<" the min of int is: "<<numeric_limits<int>::min()<<endl; cout<<" the max of int is: "<<numeric_limits<int>::max()<<endl; cout<<" the min of long is: "<<numeric_limits<long>::min()<<endl; cout<<" the max of long is: "<<numeric_limits<long>::max()<<endl; cout<<" the min of float is: "<<numeric_limits<float>::min()<<endl; cout<<" the max of float is: "<<numeric_limits<float>::max()<<endl; cout<<" the min of double is: "<<numeric_limits<double>::min()<<endl; cout<<" the max of double is: "<<numeric_limits<double>::max()<<endl; cout<<" the min of long double is: "<<numeric_limits<long double>::min()<<endl; cout<<" the max of long double is: "<<numeric_limits<long double>::max()<<endl; cout<<" the min of unsigned is: "<<numeric_limits<unsigned>::min()<<endl; cout<<" the max of unsigned is: "<<numeric_limits<unsigned>::max()<<endl; }
[chaos@localhost cpp]$ g++ -o 4.5 ./4.5.cpp [chaos@localhost cpp]$ ./4.5 the min of char is: -128 the max of char is: 127 the min of short is: -32768 the max of short is: 32767 the min of int is: -2147483648 the max of int is: 2147483647 the min of long is: -9223372036854775808 the max of long is: 9223372036854775807 the min of float is: 1.17549e-38 the max of float is: 3.40282e+38 the min of double is: 2.22507e-308 the max of double is: 1.79769e+308 the min of long double is: 3.3621e-4932 the max of long double is: 1.18973e+4932 the min of unsigned is: 0 the max of unsigned is: 4294967295
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原文地址:http://blog.csdn.net/armor51/article/details/51360612