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Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Assume that the total area is never beyond the maximum possible value of int.
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Special thanks to @mithmatt for adding this problem, creating the above image and all test cases.
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1 public class Solution { 2 public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { 3 int totalarea = (C-A)*(D-B) + (G-E)*(H-F); 4 if(A>G || D<F || C<E || B>H) 5 return totalarea; 6 int tmp = (Math.min(D,H) - Math.max(B,F)) * (Math.min(C,G) - Math.max(A,E)); 7 return totalarea - tmp; 8 } 9 }
判断两个矩形是否有交集，有交集的话，减去重叠的即可。没有交集的话，直接返回两个矩形的面积和。
223. Rectangle Area JAVA solutions
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原文地址：http://www.cnblogs.com/guoguolan/p/5485831.html
