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Invert a binary tree.
4 / 2 7 / \ / 1 3 6 9
to
4 / 7 2 / \ / 9 6 3 1
代码实现
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 TreeNode* invertTree(TreeNode* root) { 13 if(!root) return root; 14 if(root->left!=nullptr||root->right!=nullptr) 15 { 16 swap(root->left,root->right); 17 root->left=invertTree(root->left); 18 root->right=invertTree(root->right); 19 } 20 return root; 21 } 22 };
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原文地址:http://www.cnblogs.com/19q3/p/5492952.html