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以前常做的一件事就是把返回的json复制到格式化工具里看内容,Json格式化方法那么多直接格式化LOG不是很省事。
很早前写的简单LOG类(Log.java)
import android.text.TextUtils; /** * 日志信息 * * @author Harlan Song * @createDate 2013-2-8 */ public class Log { /** * 日志开关 */ private static boolean isDebug = true; private static final String AUTHOR ="HARLAN -->"; public static void debug(boolean status){ isDebug = status; } public static void d(String tag, String message) { if (isDebug) { android.util.Log.d(tag,AUTHOR + message); } } public static void i(String tag, String message) { if (isDebug) { android.util.Log.i(tag, AUTHOR +message); } } /** * Json格式化输出 * @param tag * @param message 内容 * @param isOutputOriginalContent 是否输入原内容 */ public static void iJsonFormat(String tag, String message,boolean isOutputOriginalContent) { if (isDebug && !TextUtils.isEmpty(message)) { if(isOutputOriginalContent) android.util.Log.i(tag, AUTHOR + message); android.util.Log.i(tag, AUTHOR +"\n" + JsonUtils.format(StringUtils.convertUnicode(message))); } } public static void w(String tag, String message) { if (isDebug) { android.util.Log.w(tag,AUTHOR + message); } } public static void e(String tag, String message) { if (isDebug) { android.util.Log.e(tag,AUTHOR + message); } } }
调用iJsonFormat就可以了,先把内容Unicode转换再格式化JSON,不然如果显示的是unicode后的内容中文看不出来也不方便.
Unicode解码方法,网上很多了。
public static String convertUnicode(String ori) { char aChar; int len = ori.length(); StringBuffer outBuffer = new StringBuffer(len); for (int x = 0; x < len; ) { aChar = ori.charAt(x++); if (aChar == ‘\\‘) { aChar = ori.charAt(x++); if (aChar == ‘u‘) { // Read the xxxx int value = 0; for (int i = 0; i < 4; i++) { aChar = ori.charAt(x++); switch (aChar) { case ‘0‘: case ‘1‘: case ‘2‘: case ‘3‘: case ‘4‘: case ‘5‘: case ‘6‘: case ‘7‘: case ‘8‘: case ‘9‘: value = (value << 4) + aChar - ‘0‘; break; case ‘a‘: case ‘b‘: case ‘c‘: case ‘d‘: case ‘e‘: case ‘f‘: value = (value << 4) + 10 + aChar - ‘a‘; break; case ‘A‘: case ‘B‘: case ‘C‘: case ‘D‘: case ‘E‘: case ‘F‘: value = (value << 4) + 10 + aChar - ‘A‘; break; default: throw new IllegalArgumentException( "Malformed \\uxxxx encoding."); } } outBuffer.append((char) value); } else { if (aChar == ‘t‘) aChar = ‘\t‘; else if (aChar == ‘r‘) aChar = ‘\r‘; else if (aChar == ‘n‘) aChar = ‘\n‘; else if (aChar == ‘f‘) aChar = ‘\f‘; outBuffer.append(aChar); } } else outBuffer.append(aChar); } return outBuffer.toString(); }
JSON格式化方法,同样是网上找的。
public static String format(String jsonStr) { int level = 0; StringBuffer jsonForMatStr = new StringBuffer(); for(int i=0;i<jsonStr.length();i++){ char c = jsonStr.charAt(i); if(level>0&&‘\n‘==jsonForMatStr.charAt(jsonForMatStr.length()-1)){ jsonForMatStr.append(getLevelStr(level)); } switch (c) { case ‘{‘: case ‘[‘: jsonForMatStr.append(c+"\n"); level++; break; case ‘,‘: jsonForMatStr.append(c+"\n"); break; case ‘}‘: case ‘]‘: jsonForMatStr.append("\n"); level--; jsonForMatStr.append(getLevelStr(level)); jsonForMatStr.append(c); break; default: jsonForMatStr.append(c); break; } } return jsonForMatStr.toString(); } private static String getLevelStr(int level){ StringBuffer levelStr = new StringBuffer(); for(int levelI = 0;levelI<level ; levelI++){ levelStr.append("\t"); } return levelStr.toString(); }
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原文地址:http://www.cnblogs.com/markdev/p/5497642.html