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Python 练习 21

时间:2016-05-26 17:14:26      阅读:205      评论:0      收藏:0      [点我收藏+]

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#!/usr/bin/python
# -*- coding: UTF-8 -*-

h = 0
leap = 1
from math import sqrt
from sys import stdout
for m in range(101,201):
    k = int(sqrt(m + 1))
    for i in range(2,k + 1):
        if m % i == 0:
            leap = 0
            break
    if leap == 1:
        print %-4d % m
        h += 1
        if h % 10 == 0:
            print ‘‘
    leap = 1
print The total is %d % h

 

Python 练习 21

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原文地址:http://www.cnblogs.com/kuihua/p/5531807.html

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