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This lessons teaches about delay and delayWhen: simple operators that time shift.
delay(number | date)
var foo = Rx.Observable.interval(500).take(5); /* --0--1--2--3--4| delay(1000) -----0--1--2--3--4| */ // delay(1000) var result = foo.delay(1000); result.subscribe( function (x) { console.log(‘next ‘ + x); }, function (err) { console.log(‘error ‘ + err); }, function () { console.log(‘done‘); }, );
var foo = Rx.Observable.interval(500).take(5); /* --0--1--2--3--4| delay(date) -----0--1--2--3--4| */ var date = new Date(new Date().getTime() + 1000); var result = foo.delay(date); result.subscribe( function (x) { console.log(‘next ‘ + x); }, function (err) { console.log(‘error ‘ + err); }, function () { console.log(‘done‘); }, );
delayWhen( function :Observable): accept a function which return an observable:
var foo = Rx.Observable.interval(500).take(5); /* --0--1--2--3--4| delayWhen(x => --------0--------...) --------0--------1--------2--------3--------4| */ // delay(1000) var result = foo.delayWhen(x => Rx.Observable.interval(x * 1000) // For each foo, it will delay 1000 * x, so ‘2‘ --> 2000, ‘3‘ ---> 3000 ); result.subscribe( function (x) { console.log(‘next ‘ + x); }, function (err) { console.log(‘error ‘ + err); }, function () { console.log(‘done‘); }, );
[RxJS] Transformation operators: delay and delayWhen
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原文地址:http://www.cnblogs.com/Answer1215/p/5535700.html