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本片继续前几篇介绍图数据库的创建，有疑问可以我的看看前两篇文章：http://www.cnblogs.com/rongyux/p/5537206.html
四 图数据库的创建
1 创建一个节点 Person {name: "My Name"}
CREATE (me:Person {name: "My Name"}) return me;
CREATE (movie:Movie {title: "Mystic River", released:1993})
RETURN movie;
2修改属性
更改属性 ： movie.tagline = "We bury our sins here, Dave. We wash them clean."
MATCH (movie:Movie) WHERE movie.title="Mystic River" SET movie.tagline = "We bury our sins here, Dave. We wash them clean." RETURN movie;
更改 ： movie.released = 2003
MATCH (movie:Movie) WHERE movie.title="Mystic River" SET movie.released = 2003 RETURN movie;
3 增加关系-边
MATCH (me:Person), (movie:Movie) WHERE me.name="My Name" AND movie.title="Mystic River" CREATE (me)-[:REVIEWED {rating:80, summary:"tragic character movie"}]->(movie);
另一种写法：
MATCH (me:Person {name:"My Name"}),
(movie:Movie {title:"Mystic River"})
CREATE (me)-[:REVIEWED {rating:80, summary:"tragic character movie"}]->(movie);
4merge：若不存在这个边，则增加这条关系：
MATCH (clint:Person),(mystic:Movie) WHERE clint.name="Clint Eastwood" AND mystic.title="Mystic River" MERGE (clint)-[:DIRECTED]->(mystic) RETURN clint, mystic;
复杂一点的例子：
增加认识 knows关系：一部电影的演员与演员，演员或导演，或导演与导演之间可能认识：
MATCH (a)-[:ACTED_IN|:DIRECTED]->()<-[:ACTED_IN|:DIRECTED]-(b) WHERE NOT (a)-[:KNOWS]-(b) MERGE (a)-[:KNOWS]->(b);
5 删除节点和边
MATCH (me:Person {name="My Name"})
OPTIONAL MATCH (me)-[r]-()
DELETE me,r;
6 长度等级输出
MATCH (node1)-[*]-(node2)
eg。MATCH (node1)-[*1..3]-(node2) : 三个长度等级的输出
7 shortestPath函数返回路径长度最短的path
MATCH p=shortestPath( (node1)-[*]-(node2) )
RETURN length(p), nodes(p)
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原文地址：http://www.cnblogs.com/rongyux/p/5537260.html
