码迷,mamicode.com
首页 > Windows程序 > 详细

破解wingide编辑器

时间:2016-05-28 20:36:21      阅读:341      评论:0      收藏:0      [点我收藏+]

标签:

先到官网下载最新版的wingide(我下载的是5.1.11-1),然后安装,打开,出现下面的界面时选第三个,然后输入“ENX27-HWM6G-XYVFA-165PG”,如下图所示:

技术分享

接下来你软件会给你反馈一个request code,如下图:

技术分享

复制这个request code,替换下面这个脚本的RequestCode变量的值:

# -*- coding: utf-8 -*-
#先安装程序,安装完成后打开注册界面,输入下面的License ID 后得到RequestCode,将RequestCode替换掉本文件的RequestCode,运行代码,得到激活码
import sha
import string
import sys
reload(sys)
sys.setdefaultencoding(utf-8)
BASE2 = 01
BASE10 = 0123456789
BASE16 = 0123456789ABCDEF
BASE30 = 123456789ABCDEFGHJKLMNPQRTVWXY
BASE36 = 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ
BASE62 = ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz
BASEMAX = string.printable
def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
    """ converts a "number" between two bases of arbitrary digits
    
    The input number is assumed to be a string of digits from the
    fromdigits string (which is in order of smallest to largest
    digit). The return value is a string of elements from todigits
    (ordered in the same way). The input and output bases are
    determined from the lengths of the digit strings. Negative 
    signs are passed through.
    
    decimal to binary
    >>> baseconvert(555,BASE10,BASE2)
    ‘1000101011‘
    
    binary to decimal
    >>> baseconvert(‘1000101011‘,BASE2,BASE10)
    ‘555‘
    
    integer interpreted as binary and converted to decimal (!)
    >>> baseconvert(1000101011,BASE2,BASE10)
    ‘555‘
    
    base10 to base4
    >>> baseconvert(99,BASE10,"0123")
    ‘1203‘
    
    base4 to base5 (with alphabetic digits)
    >>> baseconvert(1203,"0123","abcde")
    ‘dee‘
    
    base5, alpha digits back to base 10
    >>> baseconvert(‘dee‘,"abcde",BASE10)
    ‘99‘
    
    decimal to a base that uses A-Z0-9a-z for its digits
    >>> baseconvert(257938572394L,BASE10,BASE62)
    ‘E78Lxik‘
    
    ..convert back
    >>> baseconvert(‘E78Lxik‘,BASE62,BASE10)
    ‘257938572394‘
    
    binary to a base with words for digits (the function cannot convert this back)
    >>> baseconvert(‘1101‘,BASE2,(‘Zero‘,‘One‘))
    ‘OneOneZeroOne‘
    
    """
    if not ignore_negative and str(number)[0] == -:
        number = str(number)[1:]
        neg = 1
    else:
        neg = 0
    x = long(0)
    for digit in str(number):
        x = x * len(fromdigits) + fromdigits.index(digit)

    res = ‘‘
    while x > 0:
        digit = x % len(todigits)
        res = todigits[digit] + res
        x /= len(todigits)

    if neg:
        res = - + res
    return res

def SHAToBase30(digest):
    """Convert from a hexdigest form SHA hash into a more compact and
    ergonomic BASE30 representation.  This results in a 17 ‘digit‘ 
    number."""
    tdigest = ‘‘.join([ c for i, c in enumerate(digest) if i / 2 * 2 == i ])
    result = BaseConvert(tdigest, BASE16, BASE30)
    while len(result) < 17:
        result = 1 + result

    return result
def AddHyphens(code):
    """Insert hyphens into given license id or activation request to
    make it easier to read"""
    return code[:5] + - + code[5:10] + - + code[10:15] + - + code[15:]

LicenseID=ENX27-HWM6G-XYVFA-165PG
#Copy the Request Code from the dialog
RequestCode=RW537-V6NXW-GCLPK-7RE16
hasher = sha.new()
hasher.update(RequestCode)
hasher.update(LicenseID)
digest = hasher.hexdigest().upper()
lichash = RequestCode[:3] + SHAToBase30(digest)
lichash=AddHyphens(lichash)

#Calculate the Activation Code
data=[7,123,23,87]
tmp=0
realcode=‘‘
for i in data:
    for j in lichash:
        tmp=(tmp*i+ord(j))&0xFFFFF
    realcode+=format(tmp,=05X)
    tmp=0

act30=BaseConvert(realcode,BASE16,BASE30)
while len(act30) < 17:
    act30 = 1 + act30
act30=AXX+act30
act30=AddHyphens(act30)
print "The Activation Code is: "+act30

raw_input()

保存之后执行,你将得到provided activation key,如下图:

技术分享

将这个key拷贝到刚才那个界面,然后点继续就完成破解了。

破解wingide编辑器

标签:

原文地址:http://www.cnblogs.com/yestreenstars/p/5538199.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!