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比如我有下面这样一个List，里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么？
比如我输入的查询条件为“wang”，那么应该返回只包含employee1的List列表。
List list = new ArrayList(); Employee employee1 = new Employee(); employee1.setName("wangqiang"); employee1.setAge(30); list.add(employee1); Employee employee2 = new Employee(); employee2.setName("lisi"); list.add(employee2); employee2.setAge(25);
方式一：
public List search(String name,List list){ List results = new ArrayList(); Pattern pattern = Pattern.compile(name); for(int i=0; i < list.size(); i++){ Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName()); if(matcher.matches()){ results.add(list.get(i)); } } return results; }
上面那个是大小写敏感的，如果要求大小写不敏感，改成：
Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);
并且上面那个是精确查询，如果要模糊匹配，matcher.find()即可以进行模糊匹配
public List search(String name,List list){ List results = new ArrayList(); Pattern pattern = Pattern.compile(name); for(int i=0; i < list.size(); i++){ Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName()); if(matcher.find()){ results.add(list.get(i)); } } return results; }
方式二：
public class ListLike { //定义员工类 public class Employee { private String name; private int age; public int getAge() { return age; } public void setAge(int age) { this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } } public List list=new ArrayList(); //增加员工 public List addList(String name,int age){ Employee employee1 = new Employee(); employee1.setName(name); employee1.setAge(age); list.add(employee1); return list; } //显示所有员工 public void ShowList(){ for(int i=0;i<list.size();i++){ System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge()); } } //模糊查询 public List likeString(String likename){ for(int i=0;i<list.size();i++){ if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1) list.remove(i); } return list; } public static void main(String arg[]){ ListLike ll=new ListLike(); ll.addList("wuxiao",13); ll.addList("wangwang",11); ll.addList("wanghua",12); ll.addList("xiaowang",13); ll.addList("xiaoxiao",13); ll.likeString("wang"); ll.ShowList(); } }
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原文地址：http://www.cnblogs.com/azhqiang/p/5594447.html
